In the second row of the periodic table, \(\mathrm{Be}, \mathrm{N},\) and \(\mathrm{Ne}\) all have positive (unfavorable) electron affinities, whereas the other second-row elements have negative (favorable) electron affinities. Rationalize why Be, \(N,\) and Ne have unfavorable electron affinities.

Short Answer

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In the second row of the periodic table, Be, N, and Ne have unfavorable electron affinities due to their specific electronic configurations, which require energy input to accommodate an extra electron. Be and Ne have completely filled outer orbitals (\(2s^2\) for Be, and \(2s^2\) \(2p^6\) for Ne) while N has three unpaired electrons in its 2p orbitals (\(1s^2\) \(2s^2\) \(2p^3\)) which leads to increased electron-electron repulsion when adding an extra electron. These factors result in positive, unfavorable electron affinities for these elements compared to the rest of the second-row elements.

Step by step solution

01

Recall the definition of electron affinity

Electron affinity is the amount of energy released or absorbed when an electron is added to a neutral atom, resulting in a negatively charged ion. In general, favorable electron affinities are associated with a release of energy by the atom when adding electrons.
02

Understand electronic configurations

The electronic configuration of an element is a representation of the distribution of electrons across its atomic orbitals. Elements in the same group (vertical column) in the periodic table have similar electronic configurations because they have the same number of electrons in their outermost shells. With this in mind, we can analyze the electronic configurations of Be, N, and Ne to explain their electron affinities.
03

Determine the electronic configurations of Be, N, and Ne

Let's examine the electron configurations of Be, N, and Ne: 1. Be (Beryllium) - Atomic number = 4 Electronic configuration: \(1s^2\) \(2s^2\) 2. N (Nitrogen) - Atomic number = 7 Electronic configuration: \(1s^2\) \(2s^2\) \(2p^3\) 3. Ne (Neon) - Atomic number = 10 Electronic configuration: \(1s^2\) \(2s^2\) \(2p^6\)
04

Analyze the electronic configurations and explain the unfavorable electron affinities

Upon analyzing the electronic configurations of Be, N, and Ne, we can observe the following: 1. Be has a completely filled 2s orbital. Adding another electron would require promotion to the higher energy 2p orbital, which needs energy input, leading to an unfavorable electron affinity. 2. N has three unpaired electrons in its 2p orbitals. Adding another electron results in one of the 2p orbitals having two electrons with the same spin, which increases electrostatic repulsion. Therefore, energy must be provided to the system to allow this process to happen, making the electron affinity unfavorable. 3. Ne has a completely filled 2p orbital. Neon's electron configuration corresponds to a stable noble gas configuration, with completely filled s and p orbitals in the outer shell. To add an additional electron, it must be placed in a 3s orbital with higher energy, which requires energy input. Thus, Ne has an unfavorable electron affinity.
05

Conclusion

In summary, Be, N, and Ne have unfavorable electron affinities due to their specific electronic configurations, which require energy input to accommodate an extra electron. Be and Ne have completely filled outer orbitals, whereas N's electron affinity is affected by inducing an increase in electron-electron repulsion within its 2p orbitals.

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