Cesium was discovered in natural mineral waters in 1860 by R. W. Bunsen and G. R. Kirchhoff, using the spectroscope they invented in \(1859 .\) The name came from the Latin caesius ("sky blue") because of the prominent blue line observed for this element at \(455.5 \mathrm{nm} .\) Calculate the frequency and energy of a photon of this light.

Short Answer

Expert verified
The frequency of the photon is approximately \(6.585 \times 10^{14} \, Hz\) and the energy of the photon is approximately \(4.359 \times 10^{-19} \, J\).

Step by step solution

01

Convert wavelength to meters

First, we need to convert the given wavelength (455.5 nm) to meters. We know that 1 nm is equal to \(1 \times 10^{-9}\) m. So, we can convert the wavelength to meters as follows: \(455.5 \, nm \times \frac{1\,m}{1 \times 10^9\, nm} = 4.555 \times 10^{-7} \, m\)
02

Calculate the frequency

Next, we will use the equation \(ν = \frac{c}{λ}\) to calculate the frequency of the photon. The speed of light (c) is approximately \(3 \times 10^8 \, m/s\). So, the frequency will be: \(ν = \frac{3 \times 10^8\, m/s}{4.555 \times 10^{-7}\, m} ≈ 6.585 \times 10^{14} \, Hz\)
03

Calculate the energy

Finally, we will calculate the energy of the photon using Planck's constant (h) and the frequency (ν). Planck's constant is approximately \(6.626 \times 10^{-34} \, Js\). The energy of the photon can be calculated as follows: \(E = hν = (6.626 \times 10^{-34}\, Js)(6.585 \times 10^{14}\, Hz) ≈ 4.359 \times 10^{-19} \, J\) So, the frequency of the photon is approximately \(6.585 \times 10^{14} \, Hz\) and the energy of the photon is approximately \(4.359 \times 10^{-19} \, J\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free