When concentrated hydrochloric acid is added to a red solution containing the \(\operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) complex ion, the solution turns blue as the tetrahedral \(\mathrm{CoCl}_{4}^{2-}\) complex ion forms. Explain this color change.

Short Answer

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The color change from red to blue when concentrated hydrochloric acid is added to a solution containing the \(\operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) complex is due to the replacement of water molecules with chloride ions, forming the \(\mathrm{CoCl}_{4}^{2-}\) complex. This new ligand environment changes the splitting of the cobalt ion's d-orbitals and the electronic transitions within the complex. Consequently, the complexes absorb light at different wavelengths, causing the observed color change; the initial complex appears red while the final complex appears blue.

Step by step solution

01

Identify the initial complex and its reaction with hydrochloric acid

The starting complex is \(\operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\), which has a red color. When concentrated hydrochloric acid is added, it results in the formation of the \(\mathrm{CoCl}_{4}^{2-}\) complex, which has a blue color.
02

Describe the reaction between the cobalt complex and hydrochloric acid

When concentrated hydrochloric acid is added to the solution, its high concentration of chloride ions (Cl-) will replace the water molecules surrounding the cobalt ion. This results in the following reaction: \[ \operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+} + 4\mathrm{Cl}^{-} \rightarrow \mathrm{CoCl}_{4}^{2-} + 6\mathrm{H}_{2}\mathrm{O} \] In this reaction, the hexaaquacobalt(II) complex ion reacts with chloride ions to form the tetrachlorocobaltate(II) complex ion and releases water as a product.
03

Explain the color change based on electronic transitions

The observed color change is due to the electronic transition occurring within the ligand field of the cobalt complex. In the original \(\operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) complex, the cobalt ion is in an octahedral environment surrounded by water molecules. This arrangement causes the d-orbitals to split into two levels: t2g and eg. When hydrochloric acid is added and the complex changes to \(\mathrm{CoCl}_{4}^{2-}\), the cobalt ion now finds itself in a different, tetrahedral ligand field environment surrounded by chloride ions. This change in the ligand environment also changes the splitting of the d-orbitals, resulting in different energy gaps between the orbitals. As a consequence, the absorbed light's wavelength - and therefore the color that our eyes perceive - is different for the two complexes. The \(\operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) complex absorbs blue light and appears red, while the \(\mathrm{CoCl}_{4}^{2-}\) complex absorbs yellow-orange light and appears blue.
04

Summary

To summarize, the concentrated hydrochloric acid leads to a replacement of water molecules in the \(\operatorname{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) complex by chloride ions, forming the \(\mathrm{CoCl}_{4}^{2-}\) complex. The new ligand environment results in a change of the electronic transitions happening in the cobalt complex, leading to a different color being absorbed by the complex. The result is a color change from red to blue in the solution.

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