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Chapter 20: Problem 35

Name the following coordination compounds. a. \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{2}\) b. \(\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{I}_{3}\) c. \(\mathrm{K}_{2}\left[\mathrm{PtCl}_{4}\right]\) d. \(K_{4}\left[P_{t} C l_{6}\right]\) e. \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\) f. \(\left[\operatorname{Co}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{3}\right]\)

Short Answer

Expert verified
a. hexaamminecobalt(II) chloride b. hexaaquacobalt(III) iodide c. potassium tetrachloridoplatinate(IV) d. potassium hexachloridoplatinate(IV) e. pentaamminechloridocobalt(II) chloride f. 1. triamminetrinitrocobalt(III) 2. triamminetrititocobalt(III)

Step by step solution

01

Identify the central metal atom/ion and ligands

In this compound, the central metal ion is Cobalt (Co) and the ligands are six Ammonia (NH\(_{3}\)) molecules and two Chloride (Cl\(^{-}\)) ions.
02

Determine the oxidation state of the central metal ion

Since there are two Cl\(^{-}\) ions outside the coordination sphere, the net charge on the coordination sphere is +2. Therefore, the oxidation state of Cobalt is +2. We will represent this with "II".
03

Name the compound

Combining all the above information, the name will be: hexaamminecobalt(II) chloride. b. \(\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\mathrm{I}_{3}\)
04

Identify the central metal atom/ion and ligands

The central metal ion is Cobalt (Co) and the ligands are six water (H\(_{2}\)O) molecules and three Iodide (I\(^{-}\)) ions.
05

Determine the oxidation state of the central metal ion

As there are three I\(^{-}\) ions outside the coordination sphere, the net charge on the coordination sphere is +3. Therefore, the oxidation state of Cobalt is +3 or "III".
06

Name the compound

Combining all the above information, the name will be: hexaaquacobalt(III) iodide. c. \(\mathrm{K}_{2}\left[\mathrm{PtCl}_{4}\right]\)
07

Identify the central metal atom/ion and ligands

The central metal ion is Platinum (Pt) and the ligands are four Chloride (Cl\(^{-}\)) ions. There are also two Potassium (K\(^{+}\)) ions which are not part of the coordination sphere.
08

Determine the oxidation state of the central metal ion

In this compound, we have four Cl\(^{-}\) ions and two K\(^{+}\) ions outside the coordination sphere. The net charge on the coordination sphere is neutral. Therefore, the oxidation state of Platinum is +4 or "IV".
09

Name the compound

Combining all the above information, the name will be: potassium tetrachloridoplatinate(IV). d. \(K_{4}\left[P_{t} C l_{6}\right]\)
10

Identify the central metal atom/ion and ligands

The central metal ion is Platinum (Pt) and the ligands are six Chloride (Cl\(^{-}\)) ions. There are also four Potassium (K\(^{+}\)) ions not part of the coordination sphere.
11

Determine the oxidation state of the central metal ion

In this compound, we have four K\(^{+}\) ions and six Cl\(^{-}\) ions outside the coordination sphere. The net charge on the coordination sphere is -2. Therefore, the oxidation state of Platinum is +4 or "IV".
12

Name the compound

Combining all the above information, the name will be: potassium hexachloridoplatinate(IV). e. \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right]\mathrm{Cl}_{2}\)
13

Identify the central metal atom/ion and ligands

The central metal ion is Cobalt (Co) and the ligands are five Ammonia (NH\(_{3}\)) molecules and one Chloride (Cl\(^{-}\)) ion inside the coordination sphere. There are also two Chloride (Cl\(^{-}\)) ions outside the coordination sphere.
14

Determine the oxidation state of the central metal ion

Since there are two Cl\(^{-}\) ions outside the coordination sphere, the net charge on the coordination sphere is +2. Therefore, the oxidation state of Cobalt is +2 or "II".
15

Name the compound

Combining all the above information, the name will be: pentaamminechloridocobalt(II) chloride. f. \(\left[\operatorname{Co}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{3}\right]\)
16

Identify the central metal atom/ion and ligands

The central metal ion is Cobalt (Co) and the ligands are three Ammonia (NH\(_{3}\)) molecules and three Nitrite (NO\(_{2}^{-}\)) ions. Note that Nitrite can act as a ligand in two ways, either through Nitrogen (called nitro) or through Oxygen (called nitrito). In this case, it is not specified which one, so we will consider both possibilities.
17

Determine the oxidation state of the central metal ion

The coordination sphere has a net charge of 0 as there are no other ions in the compound. Therefore, the oxidation state of Cobalt is +3 or "III".
18

Name the compound considering both ligand possibilities

There are two possible names for this compound depending on whether nitrite is bonded through Nitrogen or Oxygen: 1. triamminetrinitrocobalt(III) (if nitrite is bonded through Nitrogen) 2. triamminetrititocobalt(III) (if nitrite is bonded through Oxygen)

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Most popular questions from this chapter

Molybdenum is obtained as a by-product of copper mining or is mined directly (primary deposits are in the Rocky Mountains in Colorado). In both cases it is obtained as \(\mathrm{MoS}_{2},\) which is then converted to \(\mathrm{MoO}_{3}\). The \(\mathrm{MoO}_{3}\) can be used directly in the production of stainless steel for high-speed tools (which accounts for about \(85 \%\) of the molybdenum used). Molybdenum can be purified by dissolving \(\mathrm{MoO}_{3}\) in aqueous ammonia and crystallizing ammonium molybdate. Depending on conditions, either \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Mo}_{2} \mathrm{O}_{7}\) or \(\left(\mathrm{NH}_{4}\right)_{6} \mathrm{Mo}_{7} \mathrm{O}_{24} \cdot 4 \mathrm{H}_{2} \mathrm{O}\) is obtained. a. Give names for \(\mathrm{MoS}_{2}\) and \(\mathrm{MoO}_{3}\) b. What is the oxidation state of Mo in each of the compounds mentioned above?

The \(\mathrm{CrF}_{6}^{4-}\) ion is known to have four unpaired electrons. Does the \(\mathrm{F}^{-}\) ligand produce a strong or weak field?

Write electron configurations for the following ions. a. \(\mathrm{Ni}^{2+}\) b. \(\mathrm{Cd}^{2+}\) c. \(\mathrm{Zr}^{3+}\) and \(\mathrm{Zr}^{4+}\) d. \(\mathrm{Os}^{2+}\) and \(\mathrm{Os}^{3+}\)

\(\mathrm{CoCl}_{4}^{2-}\) forms a tetrahedral complex ion and \(\mathrm{Co}(\mathrm{CN})_{6}^{3-}\) forms an octahedral complex ion. What is wrong about the following statements concerning each complex ion and the \(d\) orbital splitting diagrams? a. \(\mathrm{CoCl}_{4}^{2-}\) is an example of a strong-field case having two unpaired electrons. b. Because \(\mathrm{CN}^{-}\) is a weak-field ligand, \(\mathrm{Co}(\mathrm{CN})_{6}^{3-}\) will be a low-spin case having four unpaired electrons.

The following statements discuss some coordination compounds. For each coordination compound, give the complex ion and the counterions, the electron configuration of the transition metal, and the geometry of the complex ion. a. \(\mathrm{CoCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\) is a compound used in novelty devices that predict rain. b. During the developing process of black-and-white film, silver bromide is removed from photographic film by the fixer. The major component of the fixer is sodium thiosulfate. The equation for the reaction is: \(\begin{aligned} \operatorname{AgBr}(s)+2 \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3}(a q) & \longrightarrow \\\ \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right](a q)+& \mathrm{NaBr}(a q) \end{aligned}\) c. In the production of printed circuit boards for the electronics industry, a thin layer of copper is laminated onto an insulating plastic board. Next, a circuit pattern made of a chemically resistant polymer is printed on the board. The unwanted copper is removed by chemical etching, and the protective polymer is finally removed by solvents. One etching reaction is: \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q)+\mathrm{Cu}(s) \longrightarrow\) \(2 \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}(a q)\)
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