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Chapter 20: Problem 79

Give formulas for the following. a. hexakis(pyridine) cobalt(III) chloride b. pentaammineiodochromium(III) iodide c. tris(ethylenediamine)nickel(II) bromide d. potassium tetracyanonickelate(II) e. tetraamminedichloroplatinum(IV) tetrachloroplatinate(II)

Short Answer

Expert verified
The formulas for the given compounds are: a. \([Co(pyridine)_6]Cl_3\) b. \([Cr(NH_3)_5I]I_2\) c. \([Ni(ethylenediamine)_3]Br_2\) d. \( K_2[Ni(CN)_4]\) e. \([Pt(NH_3)_4Cl_2][PtCl_4]\)

Step by step solution

01

Identify the ligands and metal ion

We have hexakis(pyridine) as the ligand and Cobalt(III) as the central metal ion.
02

Determine the charges of the components

Cobalt(III) refers to a 3+ charge on the Cobalt ion. The pyridine ligand is neutral.
03

Write the formula

With 6 pyridine ligands and one Cobalt(III) ion, the complex cation will be [Co(pyridine)_6]^3+. To balance the charge, we need 3 chloride ions: Cl^-. The final formula is [Co(pyridine)_6]Cl_3. b. pentaammineiodochromium(III) iodide
04

Identify the ligands and metal ion

We have pentaammine and iodo as the ligands and Chromium(III) as the central metal ion.
05

Determine the charges of the components

Chromium(III) refers to a 3+ charge on the Chromium ion. The ammine ligands are neutral, and the iodo ligand has a 1- charge.
06

Write the formula

The complex cation will be [Cr(NH_3)_5I]^2+. To balance the charge, we need 2 iodide ions: I^-. The final formula is [Cr(NH_3)_5I]I_2. c. tris(ethylenediamine)nickel(II) bromide
07

Identify the ligands and metal ion

We have tris(ethylenediamine) as the ligand and Nickel(II) as the central metal ion.
08

Determine the charges of the components

Nickel(II) refers to a 2+ charge on the Nickel ion. The ethylenediamine ligand is neutral.
09

Write the formula

The complex cation will be [Ni(ethylenediamine)_3]^2+. To balance the charge, we need 2 bromide ions: Br^-. The final formula is [Ni(ethylenediamine)_3]Br_2. d. potassium tetracyanonickelate(II)
10

Identify the ligands and metal ion

We have tetracyano as the ligand and Nickel(II) as the central metal ion, and potassium as the counterion.
11

Determine the charges of the components

Nickel(II) refers to a 2+ charge on the Nickel ion. The cyanide ligand has a 1- charge. The potassium ion has a 1+ charge.
12

Write the formula

The complex anion will be [Ni(CN)_4]^2-. To balance the charge, we need 2 potassium ions: K^+. The final formula is K_2[Ni(CN)_4]. e. tetraamminedichloroplatinum(IV) tetrachloroplatinate(II)
13

Identify the ligands and metal ion

We have tetraammine and dichloro as the ligands, and Platinum(IV) as the first central metal ion. For the second part, we have tetrachloro as the ligand and Platinum(II) as the second central metal ion.
14

Determine the charges of the components

Platinum(IV) refers to a 4+ charge on the first Platinum ion. Platinum(II) refers to a 2+ charge on the second Platinum ion. The ammine ligands are neutral, while the chloro ligands have a 1- charge.
15

Write the formula

The complex cation will be [Pt(NH_3)_4Cl_2]^2+. The complex anion will be [PtCl_4]^2-. Combining the two, the final formula is [Pt(NH_3)_4Cl_2][PtCl_4].

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Most popular questions from this chapter

The complex ion \(\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) has an absorption maximum at around \(800 \mathrm{nm} .\) When four ammonias replace water, \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}^{2+},\) the absorption maximum shifts to around \(600 \mathrm{nm} .\) What do these results signify in terms of the relative field splittings of \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\) ? Explain.

Which of the following ions is(are) expected to form colored octahedral aqueous complex ions? a. \(\mathrm{Zn}^{2+}\) b. \(\mathrm{Cu}^{2+}\) c. \(\mathrm{Mn}^{3+}\) d. \(\mathrm{Ti}^{4+}\)

The complex ion \(\mathrm{Ru}\) (phen) \(_{3}^{2+}\) has been used as a probe for the structure of DNA. (Phen is a bidentate ligand.) a. What type of isomerism is found in \(\mathrm{Ru}(\text { phen })_{3}^{2+} ?\) b. \(\mathrm{Ru}(\text { phen })_{3}^{2+}\) is diamagnetic (as are all complex ions of \(\mathrm{Ru}^{2+}\) ). Draw the crystal field diagram for the \(d\) orbitals in this complex ion.$

Draw all geometrical and linkage isomers of square planar \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{SCN})_{2}\)

Give formulas for the following. a. potassium tetrachlorocobaltate(II) b. aquatricarbonylplatinum(II) bromide c. sodium dicyanobis(oxalato)ferrate(III) d. triamminechloroethylenediaminechromium(III) iodide
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