Which of the following compounds or ions exhibit resonance? a. \(\mathrm{O}_{3}\) b. CNO- c. \(A s I_{3}\) d. \(\mathrm{CO}_{3}^{2-}\) \(\mathbf{e}, \quad A s F_{3}\)

Short Answer

Expert verified
The compounds/ions that exhibit resonance are \(O_3\), CNO-, and \(\mathrm{CO}_{3}^{2-}\).

Step by step solution

01

Draw Lewis Structures of the Compounds and Ions

First, we will draw the Lewis structures for each compound/ion to analyze their electronic structure. a. O3: Oxygen has 6 valence electrons, so the central oxygen atom will share 2 electrons with each of the other two oxygen atoms, making a single bond with each of them. The non-bonding electrons will be the lone pairs. b. CNO-: Carbon has 4 valence electrons, nitrogen has 5, and oxygen has 6. In this case, we'll need single, double, and triple bonds to achieve their respective octets, while the negative charge on the compound represents one extra electron. c. AsI3: Arsenic has 5 valence electrons, and iodine has 7. The central arsenic atom will make single bonds with each of the three iodine atoms to achieve its octet. d. CO3^(2-): Carbon has 4 valence electrons, while oxygen has 6. The central carbon will form single/double bonds with the oxygen atoms. The ion has a charge of -2, which means there are two extra electrons available. e. AsF3: Arsenic has 5 valence electrons and fluorine has 7. The central arsenic atom will form single bonds with each of the three fluorine atoms.
02

Check for Resonance Structures

We will examine each Lewis structure and determine if it has resonance structures. a. O3: Two resonance structures can be formed by changing the location of the double bond between the oxygens. This compound exhibits resonance. b. CNO-: The compound has multiple resonance structures by changing the location of the double and triple bonds. The ions can be arranged in C-N≡O, or C=N=O, or N≡C-O configurations among others. Thus, CNO- exhibits resonance. c. AsI3: Arsenic and iodine atoms are both satisfied with their octets in the drawn structure and neither can form additional bonds due to their octet requirement. Hence, no resonance occurs in AsI3. d. CO3^(2-): The carbonate ion, CO3^(2-), exhibits resonance because there are several valid Lewis structures that can be made by moving the double bond to different oxygen atoms, while maintaining the overall negative charge. e. AsF3: Similar to AsI3, arsenic and fluorine atoms are satisfied with their octets with the existing single bonds. There is no possibility of forming additional bonds without violating octet rule; therefore, no resonance occurs in AsF3. In conclusion, the compounds/ions that exhibit resonance are \(O_3\), CNO-, and \(\mathrm{CO}_{3}^{2-}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Without using Fig. \(3-4,\) predict which bond in each of the following groups will be the most polar. a. \(C-F, S i-F, G e-F\) b. \(P-C\) or \(S-C\) \(\mathbf{c} . \mathbf{S}-\mathbf{F}, \mathbf{S}-\mathbf{C} \mathbf{l}, \mathbf{S}-\mathbf{B r}\) d. \(\mathrm{Ti}-\mathrm{Cl}, \mathrm{Si}-\mathrm{Cl}, \mathrm{Ge}-\mathrm{Cl}\)

Which compound in each of the following pairs of ionic substances has the most negative lattice energy? Justify your answers. a. NaCl, KCl b. LiF, LiCl c. \(\mathrm{Mg}(\mathrm{OH})_{2}, \mathrm{MgO}\) d. \(\mathrm{Fe}(\mathrm{OH})_{2}, \mathrm{Fe}(\mathrm{OH})_{3}\) e. \(\mathrm{NaCl}, \mathrm{Na}_{2} \mathrm{O}\) f. \(\mathrm{MgO}, \mathrm{BaS}\)

The designations \(1 \mathrm{A}\) through \(8 \mathrm{A}\) used for certain families of the periodic table are helpful for predicting the charges on ions in binary ionic compounds. In these compounds, the metals generally take on a positive charge equal to the family number, while the nonmetals take on a negative charge equal to the family number minus \(8 .\) Thus the compound between sodium and chlorine contains \(\mathrm{Na}^{+}\) ions and \(\mathrm{Cl}^{-}\) ions and has the formula NaCl. Predict the formula and the name of the binary compound formed from the following pairs of elements. a. Ca and N b. \(K\) and 0 c. \(\mathrm{Rb}\) and \(\mathrm{F}\) d. \(\mathrm{Mg}\) and \(\mathrm{S}\) e. Ba and I f. Al and Se g. Cs and \(P\) h. In and Br

Order the following species with respect to carbon-oxygen bond length (longest to shortest). $$\mathrm{CO}, \quad \mathrm{CO}_{2}, \quad \mathrm{CO}_{3}^{2-}, \quad \mathrm{CH}_{3} \mathrm{OH}$$ What is the order from the weakest to the strongest carbonoxygen bond? \(\left(\mathrm{CH}_{3} \mathrm{OH} \text { exists as } \mathrm{H}_{3} \mathrm{C}-\mathrm{OH} .\right)\)

For each of the following atomic numbers, use the periodic table to write the formula (including the charge) for the simple ion that the element is most likely to form in ionic compounds. a. 13 b. 34 c. 56 d. 7 e. 87 f. 35

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free