Given the following information: Energy of sublimation of \(\mathrm{Li}(s)=166 \mathrm{kJ} / \mathrm{mol}\) Bond energy of \(\mathrm{HCl}=427 \mathrm{kJ} / \mathrm{mol}\) Ionization energy of \(\mathrm{Li}(g)=520 . \mathrm{kJ} / \mathrm{mol}\) Electron affinity of \(\mathrm{Cl}(g)=-349 \mathrm{kJ} / \mathrm{mol}\) Lattice energy of \(\mathrm{LiCl}(s)=-829 \mathrm{kJ} / \mathrm{mol}\) Bond energy of \(\mathrm{H}_{2}=432 \mathrm{kJ} / \mathrm{mol}\) Calculate the net change in energy for the following reaction: $$ 2 \mathrm{Li}(s)+2 \mathrm{HCl}(g) \longrightarrow 2 \mathrm{LiCl}(s)+\mathrm{H}_{2}(g) $$

Short Answer

Expert verified
The net change in energy for the reaction \(2 \mathrm{Li}(s)+2 \mathrm{HCl}(g) \longrightarrow 2 \mathrm{LiCl}(s)+\mathrm{H}_{2}(g)\) is -497 kJ/mol, indicating that it is an exothermic reaction.

Step by step solution

01

Write down the energies of bond breaking

We will start by listing the energy changes associated with the breaking of chemical bonds in the reactants. For this reaction, we need to break the \(\mathrm{Li}(s)\), and \(\mathrm{HCl}(g)\) bonds. The energy values for these processes respectively are: \(\mathrm{Li}(s)=166 \mathrm{kJ/mol}\), and \(\mathrm{HCl}(g)=427 \mathrm{kJ/mol}\).
02

Write down the energies of bond formation

Next, we list the energy changes associated with the formation of chemical bonds in the products. For this reaction, we need to form the \(\mathrm{LiCl}(s)\) and \(\mathrm{H}_2(g)\) bonds. The energy values for these processes respectively are: \(\mathrm{LiCl}(s)=-829 \mathrm{kJ/mol}\) and \(\mathrm{H}_2(g)=-432 \mathrm{kJ/mol}\).
03

Consider the energy values for ionization and electron affinity

The given reaction also involves the ionization of \(\mathrm{Li}(g)\) and the electron affinity of \(\mathrm{Cl}(g)\). These energy values respectively are: \(\mathrm{Li}(g)=520 \mathrm{kJ/mol}\) and \(\mathrm{Cl}(g)=-349 \mathrm{kJ/mol}\).
04

Calculate the net energy change for the reaction

In order to calculate the net energy change for this reaction, we will sum the energy changes associated with each part of the reaction, considering both bond breaking and bond formation. Net energy change= (Energy of bond breaking) + (Energy of bond formation) + (Ionization energy) + (Electron affinity) Net energy change = (166 kJ/mol + 427 kJ/mol) + (-829 kJ/mol + (-432 kJ/mol)) + (520 kJ/mol) + (-349 kJ/mol) Net energy change = (593 kJ/mol) + (-1261 kJ/mol) + 520 kJ/mol + (-349 kJ/mol) Net energy change = -497 kJ/mol The net change in energy for this reaction is -497 kJ/mol. This means that the reaction is exothermic, releasing 497 kJ of energy per mole of reactants.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Identify each of the following elements: a. a member of the same family as oxygen whose most stable ion contains 54 electrons b. a member of the alkali metal family whose most stable ion contains 36 electrons c. a noble gas with 18 protons in the nucleus d. a halogen with 85 protons and 85 electrons

Write Lewis structures that obey the octet rule (duet rule for H) for each of the following molecules. Carbon is the central atom in \(\mathrm{CH}_{4}\), nitrogen is the central atom in \(\mathrm{NH}_{3}\), and oxygen is the central atom in \(\mathrm{H}_{2} \mathrm{O}\). a. \(\mathrm{F}_{2}\) \(\mathbf{b} . \mathbf{O}_{2}\) c. CO d. \(\overline{\mathrm{CH}_{4}}\) \(\mathbf{e} . \mathrm{NH}_{3}\) \(\mathbf{f .} \quad \mathbf{H}_{2} \mathbf{O}\) g. IIF

Write electron configurations for the most stable ion formed by each of the elements Te, \(\mathrm{Cl}, \mathrm{Sr},\) and \(\mathrm{Li}\) (when in stable ionic compounds).

Give an example of an ionic compound where both the anion and the cation are isoelectronic with each of the following noble gases. a. Ne b. Arr c. Kr d. Xe

Each of the following compounds is incorrectly named. What is wrong with each name, and what is the correct name for each compound? a. \(\mathrm{FeCl}_{3},\) iron chloride b. \(\mathrm{NO}_{2},\) nitrogen(IV) oxide c. \(\mathrm{CaO},\) calcium(II) monoxide d. \(\mathrm{Al}_{2} \mathrm{S}_{3},\) dialuminum trisulfide e. \(\mathrm{Mg}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2},\) manganese diacetate f. \(\mathrm{FePO}_{4},\) iron(II) phosphide g. \(\mathrm{P}_{2} \mathrm{S}_{5},\) phosphorus sulfide h. \(\mathrm{Na}_{2} \mathrm{O}_{2},\) sodium oxide

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free