Predict the empirical formulas of the ionic compounds formed from the following pairs of elements. Name each compound. a. Al and Cl b. Na and O c. Sr and F d. Ca and Se

Short Answer

Expert verified
a. AlCl₃ - Aluminium chloride b. Na₂O - Sodium oxide c. SrF₂ - Strontium fluoride d. CaSe - Calcium selenide

Step by step solution

01

a. Al and Cl

1. Determine the charges of the ions: Aluminium (Al) forms a +3 ion, while chlorine (Cl) forms a -1 ion. 2. Balance the charges: To obtain a neutral compound, we require 3 Cl ions for each Al ion. This gives us the empirical formula: AlCl₃ 3. Name the compound: The compound is named using the names of the two ions: Aluminium chloride.
02

b. Na and O

1. Determine the charges of the ions: Sodium (Na) forms a +1 ion, while oxygen (O) forms a -2 ion. 2. Balance the charges: To obtain a neutral compound, we require 2 Na ions for each O ion. This gives us the empirical formula: Na₂O 3. Name the compound: The compound is named using the names of the two ions: Sodium oxide.
03

c. Sr and F

1. Determine the charges of the ions: Strontium (Sr) forms a +2 ion, while fluorine (F) forms a -1 ion. 2. Balance the charges: To obtain a neutral compound, we require 2 F ions for each Sr ion. This gives us the empirical formula: SrF₂ 3. Name the compound: The compound is named using the names of the two ions: Strontium fluoride.
04

d. Ca and Se

1. Determine the charges of the ions: Calcium (Ca) forms a +2 ion, while selenium (Se) forms a -2 ion. 2. Balance the charges: To obtain a neutral compound, one Ca ion combines with one Se ion. This gives us the empirical formula: CaSe 3. Name the compound: The compound is named using the names of the two ions: Calcium selenide.

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