What noble gas has the same electron configuration as each of the ions in the following compounds? a. cesium sulfide b. strontium fluoride c. calcium nitride d. aluminum bromide

Short Answer

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The noble gases with the same electron configurations as the ions in the given compounds are: a. Cesium sulfide - Argon (Ar) b. Strontium fluoride - Neon (Ne) c. Calcium nitride - Neon (Ne) d. Aluminum bromide - Krypton (Kr)

Step by step solution

01

a. Cesium sulfide

First, we need to find the electron configuration of the cesium ion (Cs+) and the sulfide ion (S²⁻). 1. Cesium (Cs) has an atomic number of 55, so its electron configuration is [Xe] 6s¹. When it loses one electron to form the cesium ion (Cs+), the electron configuration will be [Xe]. 2. Sulfur (S) has an atomic number of 16, so its electron configuration is [Ne] 3s² 3p⁴. When it gains two electrons to form the sulfide ion (S²⁻), the electron configuration becomes [Ne] 3s² 3p⁶, which is the same as that of the noble gas Argon (Ar). So, the noble gas that has the same electron configuration as the ions in cesium sulfide is Argon (Ar).
02

b. Strontium fluoride

Now, let's find the electron configuration of the strontium ion (Sr²⁺) and the fluoride ion (F⁻). 1. Strontium (Sr) has an atomic number of 38, so its electron configuration is [Kr] 5s². When it loses two electrons to form the strontium ion (Sr²⁺), the electron configuration will be [Kr]. 2. Fluorine (F) has an atomic number of 9, so its electron configuration is [He] 2s² 2p⁵. When it gains one electron to form the fluoride ion (F⁻), the electron configuration becomes [He] 2s² 2p⁶, which is the same as that of the noble gas Neon (Ne). So, the noble gas that has the same electron configuration as the ions in strontium fluoride is Neon (Ne).
03

c. Calcium nitride

Next, let's find the electron configuration of the calcium ion (Ca²⁺) and the nitride ion (N³⁻). 1. Calcium (Ca) has an atomic number of 20, so its electron configuration is [Ar] 4s². When it loses two electrons to form the calcium ion (Ca²⁺), the electron configuration will be [Ar]. 2. Nitrogen (N) has an atomic number of 7, so its electron configuration is [He] 2s² 2p³. When it gains three electrons to form the nitride ion (N³⁻), the electron configuration becomes [He] 2s² 2p⁶, which is the same as that of the noble gas Neon (Ne). So, the noble gas that has the same electron configuration as the ions in calcium nitride is Neon (Ne).
04

d. Aluminum bromide

Finally, let's find the electron configuration of the aluminum ion (Al³⁺) and the bromide ion (Br⁻). 1. Aluminum (Al) has an atomic number of 13, so its electron configuration is [Ne] 3s² 3p¹. When it loses three electrons to form the aluminum ion (Al³⁺), the electron configuration will be [Ne]. 2. Bromine (Br) has an atomic number of 35, so its electron configuration is [Ar] 4s² 3d¹⁰ 4p⁵. When it gains one electron to form the bromide ion (Br⁻), the electron configuration becomes [Ar] 4s² 3d¹⁰ 4p⁶, which is the same as that of the noble gas Krypton (Kr). So, the noble gas that has the same electron configuration as the ions in aluminum bromide is Krypton (Kr).

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