Bond energy has been defined in the text as the amount of energy required to break a chemical bond, so we have come to think of the addition of energy as breaking bonds. However, in some cases the addition of energy can cause the formation of bonds. For example, in a sample of helium gas subjected to a high-energy source, some He_ molecules exist momentarily and then dissociate. Use MO theory (and diagrams) to explain why \(\mathrm{He}_{2}\) molecules can come to exist and why they dissociate.

Short Answer

Expert verified
According to Molecular Orbital Theory, He2 molecules momentarily exist under high-energy conditions due to the formation of a σ bonding molecular orbital. However, the presence of an equal number of electrons in the σ* antibonding molecular orbital leads to rapid dissociation, as the stabilization energy from bonding is canceled out by the destabilization energy from the antibonding orbital. This explanation is supported by the MO diagram for the He2 molecule and its electron configuration (σ2σ*2).

Step by step solution

01

Understanding Molecular Orbital Theory

Molecular Orbital Theory (MO theory) is a method to describe the electronic structure of molecules. It combines atomic orbitals from individual atoms to form molecular orbitals that belong to the entire molecule. These molecular orbitals can have different shapes, energies, and their occupation by electrons determines the stability of the molecule.
02

Constructing the MO diagram for Helium Molecule (He2)

For constructing the MO diagram, we need to consider atomic orbitals of the two Helium atoms (He). Each He atom has two electrons, occupying the 1s orbital. When the two He atoms come close to each other, their atomic orbitals interact, and due to their overlapping, they form two molecular orbitals: 1. Bonding Molecular Orbital (σ): This molecular orbital has lower energy than the parent atomic orbitals and is formed by the in-phase combination of the atomic orbitals. 2. Antibonding Molecular Orbital (σ*): This molecular orbital has higher energy than the parent atomic orbitals and is formed by the out-of-phase combination of the atomic orbitals. The MO diagram for He2 molecule is shown as follows: - Atomic orbitals from two He atoms are on the left and right sides. - Molecular orbitals are represented in the middle. The lower energy bonding molecular orbital (σ) is at the bottom and the higher energy antibonding molecular orbital (σ*) is at the top.
03

Determining the electron configuration for He2

Each Helium atom has 2 electrons in its 1s orbital. When forming He2, there are a total of 4 electrons to be placed in the molecular orbitals. According to Aufbau principle, electrons fill the molecular orbitals in order of increasing energy. So, two electrons will go into the bonding molecular orbital (σ) and the remaining two electrons will go into the antibonding molecular orbital (σ*). Hence, electron configuration of He2 is: σ2σ*2
04

Explaining the momentary existence and dissociation of He2 molecules

From the electron configuration of He2 (σ2σ*2), we can observe that the number of electrons in bonding orbital is equal to the number of electrons in antibonding orbital. This means that the stabilization energy provided by the electrons in bonding molecular orbital is exactly canceled by the destabilization energy due to electrons in the antibonding molecular orbital. So, when Helium gas is subjected to a high-energy source, some He2 molecules can come to exist momentarily due to the formation of σ bonding molecular orbital. However, the destabilizing effect of the electrons in σ* antibonding molecular orbital leads to the rapid dissociation of these He2 molecules. In conclusion, MO theory and MO diagrams help us understand the momentary existence and dissociation of He2 molecules under high-energy conditions. The formation of bonding and antibonding molecular orbitals and their occupation by electrons dictate the overall stability of the molecule.

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Most popular questions from this chapter

Which of the following are predicted by the molecular orbital model to be stable diatomic species? a. \(\mathrm{H}_{2}^{+}, \mathrm{H}_{2}, \mathrm{H}_{2}^{-}, \mathrm{H}_{2}^{2-}\) b. \(\mathrm{He}_{2}^{2+}, \mathrm{He}_{2}^{+}, \mathrm{He}_{2}\)

As the head engineer of your starship in charge of the warp drive, you notice that the supply of dilithium is critically low. While searching for a replacement fuel, you discover some diboron, \(\mathbf{B}_{2}\) a. What is the bond order in \(\mathrm{Li}_{2}\) and \(\mathrm{B}_{2} ?\) b. How many electrons must be removed from \(\mathrm{B}_{2}\) to make it isoelectronic with \(\mathrm{Li}_{2}\) so that it might be used in the warp drive? c. The reaction to make \(\mathrm{B}_{2}\) isoelectronic with \(\mathrm{Li}_{2}\) is generalized (where \(n=\) number of electrons determined in part b) as follows: $$\mathrm{B}_{2} \longrightarrow \mathrm{B}_{2}^{n+}+n \mathrm{e}^{-} \quad \Delta E=6455 \mathrm{kJ} / \mathrm{mol}$$ How much energy is needed to ionize \(1.5 \mathrm{kg} \mathrm{B}_{2}\) to the desired isoelectronic species?

Arrange the following molecules from most to least polar and explain your order: \(\mathrm{CH}_{4}, \mathrm{CF}_{2} \mathrm{Cl}_{2}, \mathrm{CF}_{2} \mathrm{H}_{2}, \mathrm{CCl}_{4},\) and \(\mathrm{CCl}_{2} \mathrm{H}_{2}\).

Using an MO energy-level diagram, would you expect \(\mathrm{F}_{2}\) to have a lower or higher first ionization energy than atomic fluorine? Why?

Two different compounds have the formula \(\mathrm{XeF}_{2} \mathrm{Cl}_{2}\). Write Lewis structures for these two compounds, and describe how measurement of dipole moments might be used to distinguish between them.

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