In chemistry, what is meant by the term "mole"? What is the importance of the mole concept?

Short Answer

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In chemistry, the term "mole" refers to a unit used to represent a specific quantity of particles, such as atoms, molecules, ions, or electrons in a sample of a substance. One mole of any substance contains an identical number of particles, known as Avogadro's number, approximately \(6.022 \times 10^{23}\) particles. The mole concept is crucial in chemistry as it provides a convenient way to represent large quantities of particles and relate them to mass during chemical reactions. It is used in various applications, such as understanding and balancing chemical equations, stoichiometry, determining empirical and molecular formulae, and concentration calculations. Overall, the mole concept allows us to perform precise calculations to predict and analyze chemical reactions and processes.

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01

Definition of "mole"

A mole is a unit used to represent a specific quantity of particles like atoms, molecules, ions, or electrons in a sample of a substance. One mole of any substance contains an identical number of particles known as Avogadro's number, which is approximately \(6.022 \times 10^{23}\) particles. It is important to note that a mole of different substances may have different masses, but the number of particles will always remain the same.
02

Molar mass and the mole concept

The mole concept helps simplify chemical calculations by relating the mass of a substance to the number of particles in that substance. The molar mass is defined as the mass of one mole of a substance and is usually expressed in grams per mole (g/mol). Converting between the mass and number of particles becomes very easy using the mole concept. For example, a 12-gram sample of carbon contains one mole of carbon atoms because the molar mass of carbon is 12g/mol.
03

Importance of the mole concept in chemistry

The mole concept plays a vital role in chemistry because it provides a convenient way to represent large quantities of particles and relate them to mass during chemical reactions. Some vital applications of the mole concept are: 1. Understanding and balancing chemical equations: The mole concept helps to balance chemical equations by equalizing the number of moles of reactants and products, ensuring the law of conservation of mass is obeyed. 2. Stoichiometry: By using the mole concept, we can determine the amount of reactants needed for a reaction to happen and estimate the amount of product(s) formed after the reaction. 3. Determining empirical and molecular formulae: The mole concept is also used to find the empirical and molecular formulae of compounds, helping scientists identify their constituent elements. 4. Concentration calculations: The mole concept is essential for measuring the concentration of solutions (molarity) in various fields such as industry, medicine, and research. In conclusion, the mole concept is a fundamental concept in chemistry that helps us understand the relationship between the mass, number of particles, and the reactivity of substances. Furthermore, it allows us to perform precise calculations to predict and analyze chemical reactions and processes.

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Most popular questions from this chapter

Maleic acid is an organic compound composed of \(41.39 \%\) C, \(3.47 \%\) H, and the rest oxygen. If 0.129 mole of maleic acid has a mass of \(15.0 \mathrm{g},\) what are the empirical and molecular formulas of maleic acid?

Give the balanced equation for each of the following. a. The combustion of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) forms carbon dioxide and water vapor. A combustion reaction refers to a reaction of a substance with oxygen gas. b. Aqueous solutions of lead(II) nitrate and sodium phosphate are mixed, resulting in the precipitate formation of lead(II) phosphate with aqueous sodium nitrate as the other product. c. Solid zinc reacts with aqueous HCl to form aqueous zinc chloride and hydrogen gas. d. Aqueous strontium hydroxide reacts with aqueous hydrobromic acid to produce water and aqueous strontium bromide.

An iron ore sample contains \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) plus other impurities. \(\mathrm{A}\) \(752-\mathrm{g}\) sample of impure iron ore is heated with excess carbon, producing \(453 \mathrm{g}\) of pure iron by the following reaction: $$\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{C}(s) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}(g)$$ What is the mass percent of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the impure iron ore sample? Assume that \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is the only source of iron and that the reaction is \(100 \%\) efficient.

ABS plastic is a tough, hard plastic used in applications requiring shock resistance. The polymer consists of three monomer units: acrylonitrile \(\left(\mathrm{C}_{3} \mathrm{H}_{3} \mathrm{N}\right),\) butadiene \(\left(\mathrm{C}_{4} \mathrm{H}_{6}\right),\) and styrene \(\left(\mathrm{C}_{8} \mathrm{H}_{8}\right)\) a. A sample of ABS plastic contains \(8.80 \% \mathrm{N}\) by mass. It took \(0.605 \mathrm{g}\) of \(\mathrm{Br}_{2}\) to react completely with a \(1.20-\mathrm{g}\) sample of ABS plastic. Bromine reacts 1: 1 (by moles) with the butadiene molecules in the polymer and nothing else. What is the percent by mass of acrylonitrile and butadiene in this polymer? b. What are the relative numbers of each of the monomer units in this polymer?

The aspirin substitute. acetaminophen \(\left(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{O}_{2} \mathrm{N}\right),\) is produced by the following three-step synthesis: I. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{3} \mathrm{N}(s)+3 \mathrm{H}_{2}(g)+\mathrm{HCl}(a q) \longrightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{ONCl}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)\) II. \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{ONCl}(s)+\mathrm{NaOH}(a q) \longrightarrow\) \(\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{ON}(s)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{NaCl}(a q)\) III. \(\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{ON}(s)+\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{3}(l) \longrightarrow\) \(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{O}_{2} \mathrm{N}(s)+\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(l)\) The first two reactions have percent yields of \(87 \%\) and \(98 \%\) by mass, respectively. The overall reaction yields 3 moles of acetaminophen product for every 4 moles of \(C_{6} H_{5} O_{3} N\) reacted. a. What is the percent yield by mass for the overall process? b. What is the percent yield by mass of Step III?

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