You know that chemical \(A\) reacts with chemical \(B\). You react \(10.0 \mathrm{g} A\) with \(10.0 \mathrm{g} B .\) What information do you need to determine the amount of product that will be produced? Explain.

Short Answer

Expert verified
To determine the amount of product that will be produced, you will need the balanced chemical equation for the reaction, the molar masses of the reactants (chemical A and B) and product(s). Then, convert the given mass of each reactant into moles, determine the limiting reactant, calculate the moles of product formed using stoichiometry, and finally convert the moles of product into grams using the molar mass of the product(s).

Step by step solution

01

Identify Necessary Information

You will need the balanced chemical equation representing the reaction, as well as the molar masses of the reactants (chemical A and chemical B) and the product(s).
02

Find Moles of Reactants

Convert the given mass of each reactant (A and B) into moles using their respective molar masses. To do this, divide the mass of each reactant by its molar mass. For example, for chemical A: \(moles A = \frac{10.0\mathrm{g}}{molar\ mass\ of\ A}\).
03

Determine the Limiting Reactant

Using the balanced chemical equation, compare the ratio of moles of reactants A and B to their stoichiometric ratio in the equation. The reactant which has a lower value, when dividing the moles by their respective stoichiometric coefficients, is the limiting reactant.
04

Calculate Moles of Product

Use the stoichiometry of the balanced chemical equation to determine the moles of the product formed by the limiting reactant. For example, if reactant A is the limiting reactant and x moles of product are formed for every y moles of A: \(moles\ of\ product = \frac{x}{y} \times moles\ of\ limiting\ reactant\).
05

Find the Mass of Product Produced

Convert the moles of product formed to grams using the molar mass of the product(s). Multiply the moles of the product by its molar mass: \(mass\ of\ product = moles\ of\ product \times molar\ mass\ of\ product\). In conclusion, to determine the amount of product that will be produced, you will need the balanced chemical equation, the molar masses of the reactants and product, and then perform stoichiometric calculations to find the limiting reactant and the mass of product formed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limiting Reactant
Understanding the concept of the limiting reactant is like knowing which ingredient will run out first when you're baking a cake. In chemical reactions, the limiting reactant is the substance that is completely used up first, thus determining the maximum amount of product that can be formed. It's the bottleneck of the reaction.

To identify the limiting reactant, start by calculating the number of moles of each reactant. Then, using the balanced chemical equation, compare the mole ratio of the reactants with the coefficients in the equation. The reactant that runs out first, or the one that you have less of than required according to the reaction's proportions, is the limiting reactant. This is critical to calculate because it lets you predict the amounts of products formed in a reaction.
Balanced Chemical Equation
Chemistry is all about balance. A balanced chemical equation represents exactly what happens in a chemical reaction at the most fundamental level. It tells us how many molecules of reactants combine and how many molecules of products are formed. It's crucial because it ensures the law of conservation of mass is respected, meaning matter is neither created nor destroyed.

The coefficients in a balanced equation indicate the ratios in which substances react and are formed. These ratios are the foundation of stoichiometric calculations. Without a balanced chemical equation, we cannot correctly determine the stoichiometry of the reaction, hence we can't accurately predict the amount of products or identify the limiting reactant.
Molar Mass
Every baker knows you can't start without knowing how much a cup of flour weighs. In chemistry, molar mass serves a similar purpose—it tells us the mass of one mole of a substance. It's a bridge between the mass of a material and the number of particles contained in that mass.

Since the number of particles in a reaction is fundamental but tricky to count individually, we use moles to measure them. To convert grams to moles, divide by the molar mass; to convert back, multiply moles by the molar mass. This way, molar mass allows chemists to 'count' atoms or molecules in a bulk substance, which is essential for stoichiometric calculations and determining how much of a reactant is needed, or how much of a product is produced.
Product Yield
Imagine following a recipe and trying to predict how many cookies you'll end up with—that's exactly what product yield is in chemistry. It's the actual amount of product obtained from a chemical reaction.

The theoretical yield is the maximum amount of product expected as calculated from the stoichiometry of the balanced chemical equation, assuming all the limiting reactant is used up. The actual yield is what you really get after running the reaction, often less due to inefficiencies. By comparing the actual yield to the theoretical yield, chemists can evaluate the efficiency of reaction processes. This concept is central for practical applications, such as manufacturing pharmaceuticals or designing a chemical synthesis.

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Most popular questions from this chapter

In 1987 the first substance to act as a superconductor at a temperature above that of liquid nitrogen \((77 \mathrm{K})\) was discovered. The approximate formula of this substance is \(\mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{7}\) Calculate the percent composition by mass of this material.

A common demonstration in chemistry courses involves adding a tiny speck of manganese(IV) oxide to a concentrated hydrogen peroxide \(\left(\mathrm{H}_{2} \mathrm{O}_{2}\right)\) solution. Hydrogen peroxide decomposes quite spectacularly under these conditions to produce oxygen gas and steam (water vapor). Manganese(IV) oxide is a catalyst for the decomposition of hydrogen peroxide and is not consumed in the reaction. Write the balanced equation for the decomposition reaction of hydrogen peroxide.

A compound contains only \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{N}\). Combustion of \(35.0 \mathrm{mg}\) of the compound produces \(33.5 \mathrm{mg} \mathrm{CO}_{2}\) and \(41.1 \mathrm{mg}\) \(\mathrm{H}_{2} \mathrm{O} .\) What is the empirical formula of the compound?

Many cereals are made with high moisture content so that the cereal can be formed into various shapes before it is dried. A cereal product containing \(58 \% \mathrm{H}_{2} \mathrm{O}\) by mass is produced at the rate of \(1000 .\) kg/h. What mass of water must be evaporated per hour if the final product contains only \(20 . \%\) water?

Ammonia reacts with \(\mathrm{O}_{2}\) to form either \(\mathrm{NO}(g)\) or \(\mathrm{NO}_{2}(g)\) according to these unbalanced equations: $$\begin{array}{l}\mathrm{NH}_{3}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \\\\\mathrm{NH}_{3}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\end{array}$$ In a certain experiment 2.00 moles of \(\mathrm{NH}_{3}(g)\) and 10.00 moles of \(\mathbf{O}_{2}(g)\) are contained in a closed flask. After the reaction is complete, 6.75 moles of \(\mathbf{O}_{2}(g)\) remains. Calculate the number of moles of \(\mathrm{NO}(g)\) in the product mixture: (Hint: You cannot do this problem by adding the balanced equations because you cannot assume that the two reactions will occur with equal probability.)

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