Some of the substances commonly used in stomach antacids are \(\mathrm{MgO}, \mathrm{Mg}(\mathrm{OH})_{2},\) and \(\mathrm{Al}(\mathrm{OH})_{3}\) a. Write a balanced equation for the neutralization of hydrochloric acid by each of these substances. b. Which of these substances will neutralize the greatest amount of 0.10 \(M\) HCl per gram?

Short Answer

Expert verified
a. The balanced equations for the neutralization of hydrochloric acid by MgO, Mg(OH)₂, and Al(OH)₃ are: 1. MgO + 2HCl → MgCl₂ + H₂O 2. Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O 3. Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O b. Comparing moles of HCl neutralized per gram of each substance: - MgO: 0.0496 mol HCl/g - Mg(OH)₂: 0.0343 mol HCl/g - Al(OH)₃: 0.0385 mol HCl/g MgO neutralizes the greatest amount of 0.10 M HCl per gram and is therefore the most effective antacid among these three substances.

Step by step solution

01

Write balanced chemical equations for the antacid substances with HCl

To write the balanced equations, we need to combine each antacid substance with hydrochloric acid (HCl) and balance the resulting equation. a. The reactions are: 1. Magnesium oxide (MgO) + hydrochloric acid (HCl): MgO + 2HCl → MgCl₂ + H₂O 2. Magnesium hydroxide (Mg(OH)₂) + hydrochloric acid (HCl): Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O 3. Aluminum hydroxide (Al(OH)₃) + hydrochloric acid (HCl): Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
02

Calculate the moles of HCl neutralized per gram of each substance

To do this, we need to analyze the previously balanced equations and find out the ratio of moles of HCl neutralized to the moles of each antacid substance. Then, we will find the molar mass of each substance and calculate the moles of HCl neutralized per gram of the substance. 1. MgO: - The balanced equation shows that 1 mole of MgO neutralizes 2 moles of HCl. - Molar mass of MgO = (24.31 g/mol for Mg) + (16.00 g/mol for O) = 40.31 g/mol - Moles of HCl neutralized per gram of MgO = (2 moles HCl)/(40.31 g MgO) = 0.0496 mol HCl/g 2. Mg(OH)₂: - The balanced equation shows that 1 mole of Mg(OH)₂ neutralizes 2 moles of HCl. - Molar mass of Mg(OH)₂ = (24.31 g/mol for Mg) + (2 x 17.01 g/mol for OH) = 58.33 g/mol - Moles of HCl neutralize per gram of Mg(OH)₂ = (2 moles HCl)/(58.33 g Mg(OH)₂) = 0.0343 mol HCl/g 3. Al(OH)₃: - The balanced equation shows that 1 mole of Al(OH)₃ neutralizes 3 moles of HCl. - Molar mass of Al(OH)₃ = (26.98 g/mol for Al) + (3 x 17.01 g/mol for OH) = 78.00 g/mol - Moles of HCl neutralize per gram of Al(OH)₃ = (3 moles HCl)/(78.00 g Al(OH)₃) = 0.0385 mol HCl/g
03

Determine which substance neutralizes the greatest amount of 0.10 M HCl per gram

Now that we have the moles of HCl neutralized per gram of each substance, we can compare the values and determine the most effective antacid. Moles of HCl neutralized per gram: - MgO: 0.0496 mol HCl/g - Mg(OH)₂: 0.0343 mol HCl/g - Al(OH)₃: 0.0385 mol HCl/g MgO neutralizes the greatest amount of 0.10 M HCl per gram. Therefore, MgO is the most effective antacid among the three substances.

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Most popular questions from this chapter

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