A \(25.00-\mathrm{mL}\) sample of hydrochloric acid solution requires \(24.16 \mathrm{mL}\) of \(0.106 \mathrm{M}\) sodium hydroxide for complete neutralization. What is the concentration of the original hydrochloric acid solution?

Short Answer

Expert verified
The concentration of the original hydrochloric acid solution is approximately \( 0.1024 M \).

Step by step solution

01

Write the balanced chemical equation for the neutralization reaction

In this case, the neutralization reaction involves HCl and NaOH, resulting in the formation of water (H2O) and sodium chloride (NaCl). The balanced chemical equation for the reaction is \( HCl (aq) + NaOH (aq) \to H_{2}O (l) + NaCl (aq) \)
02

Find the moles of NaOH solution

Using the given volume and molarity of NaOH, we can find the moles of NaOH. Moles of NaOH = volume × molarity Moles of NaOH = \( 24.16 mL \times 0.106 M \) It's important to note that 1 L = 1000 mL, so convert the volume in mL to L. Moles of NaOH = \( (24.16 \times 10^{-3}) L \times 0.106 M \) Moles of NaOH = \( 2.56096 \times 10^{-3} mol \)
03

Determine the moles of HCl based on the stoichiometry

From the balanced chemical equation, we know that the ratio of moles of HCl to moles of NaOH is 1:1. Thus, the moles of HCl are equal to the moles of NaOH. Moles of HCl = \( 2.56096 \times 10^{-3} mol \)
04

Calculate the concentration of HCl

We have the moles of HCl and the given volume of the HCl solution. Now, we can find the concentration of HCl. Concentration of HCl = moles of HCl / volume of HCl solution Concentration of HCl = \( \frac{2.56096 \times 10^{-3} mol}{25.00 \times 10^{-3} L} \) Concentration of HCl = \( 0.1024 M \) The concentration of the original hydrochloric acid solution is approximately 0.1024 M.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is an area of chemistry that deals with the quantitative relationships between the amounts of reactants and products in a chemical reaction. It is based on the conservation of mass and the principle of fixed proportions stated in the law of definite proportions. For a neutralization reaction, like the one involving hydrochloric acid (HCl) and sodium hydroxide (NaOH), stoichiometry tells us how much of one reactant is needed to react completely with a given amount of the other.

Understanding stoichiometry involves interpreting the coefficients in a balanced chemical equation. For example, in the equation \( HCl (aq) + NaOH (aq) \to H_{2}O (l) + NaCl (aq) \), the coefficients imply a 1:1 molar ratio between HCl and NaOH. This means that one mole of HCl will neutralize one mole of NaOH. Applying this to problem-solving, once you know the amount of NaOH, you can directly find the equivalent amount of HCl needed for neutralization because of their 1:1 stoichiometric relationship.
Molarity Calculation
Molarity is a measure of concentration in chemistry, expressed as the number of moles of a solute divided by the volume of the solution in liters. The unit of molarity is moles per liter (M). To calculate the molarity of a solution, the formula used is:\[ Molarity = \frac{moles \text{ of solute}}{volume \text{ of solution in liters}} \]

In the context of the given problem, once you have determined the moles of NaOH used in the titration, you can calculate the molarity of the HCl solution. Since the exercise provides the volume of the acid in milliliters (mL), it's crucial to convert this volume into liters before using it in the molarity equation. Dividing the moles of HCl by the volume of the HCl solution (expressed in liters) will yield its concentration in molarity.
Chemical Equation Balancing
Balancing a chemical equation is essential because it ensures that the law of conservation of mass is obeyed in a chemical reaction. It means that atoms are neither created nor destroyed, and the same number of each type of atom must be present on both sides of the equation. A balanced chemical equation has the same number of each element's atoms on both the reactant and product sides.

For the reaction presented in the exercise, \( HCl (aq) + NaOH (aq) \to H_{2}O (l) + NaCl (aq) \), the equation is already balanced. Each side has one chloride (Cl), one sodium (Na), one hydrogen (H), and one oxygen (O) atom. When using this balanced equation to solve problems, it ensures that the stoichiometric ratios reflect the true proportions of substances involved in the reaction.
Acid-Base Titration
Acid-base titration is a quantitative analytical technique used to determine the concentration of an unknown acid or base by neutralizing it with a base or acid of known concentration. The point at which the neutralization is complete is known as the equivalence point, and it is often marked by a color change if an indicator is used, or by a sudden change in pH monitored with a pH meter.

In a titration exercise like the one we have, you typically have a known volume of an acid (HCl) and you add a base (NaOH) of known concentration until neutralization is achieved. By recording the volume of the base added to reach the equivalence point, and knowing the stoichiometry of the reaction (from a balanced equation), you can calculate the concentration of the original acid solution. This technique combines knowledge of stoichiometry, molarity, and balancing equations to accurately determine the unknown concentration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write net ionic equations for the reaction, if any, that occurs when aqueous solutions of the following are mixed. a. chromium(III) chloride and sodium hydroxide b. silver nitrate and ammonium carbonate c. copper(II) sulfate and mercury(I) nitrate d. strontium nitrate and potassium iodide

Consider the reaction between sodium metal and fluorine ( \(\mathbf{F}_{2}\) ) gas to form sodium fluoride. Using oxidation states, how many electrons would each sodium atom lose, and how many electrons would each fluorine atom gain? How many sodium atoms are needed to react with one fluorine molecule? Write a balanced equation for this reaction.

Citric acid, which can he ohtained from lemon juice, has the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}\). A 0.250 -g sample of citric acid dissolved in \(25.0 \mathrm{mL}\) of water requires \(37.2 \mathrm{mL}\) of \(0.105 \mathrm{M}\) NaOH for complete neutralization. What number of acidic hydrogens per molecule does citric acid have?

Assign the oxidation state for nitrogen in each of the following. a. \(\mathrm{Li}_{3} \mathrm{N}\) b. \(\mathrm{NH}_{3}\) \(\mathbf{c} . \mathrm{N}_{2} \mathrm{H}_{4}\) d. NO e. \(\mathrm{N}_{2} \mathrm{O}\) \(\mathbf{f} . \mathrm{NO}_{2}\) g. \(\mathrm{NO}_{2}^{-}\) h. \(\mathrm{NO}_{3}^{-}\) \(\mathbf{i} . \quad \mathbf{N}_{2}\)

What volume of each of the following acids will react completely with \(50.00 \mathrm{mL}\) of \(0.200 \mathrm{M} \mathrm{NaOH} ?\) a. \(0.100 M\) HCl b. \(0.150 M\) HNO \(_{3}\) c. \(0.200 \mathrm{M} \mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) (1 acidic hydrogen)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free