Draw a qualitative graph to show how the first property varies with the second in each of the following (assume 1 mole of an ideal gas and \(T\) in kelvin). a. \(P V\) versus \(V\) with constant \(T\) b. \(P\) versus \(T\) with constant \(V\) c. \(T\) versus \(V\) with constant \(P\) d. \(P\) versus \(V\) with constant \(T\) e. \(P\) versus \(1 / V\) with constant \(T\) f. \(P V / T\) versus \(P\)

Short Answer

Expert verified
Here are the qualitative graphs for the given scenarios: a. PV versus V (Constant T): Horizontal straight line parallel to the V-axis. b. P versus T (Constant V): Straight line that passes through the origin with a positive slope. c. T versus V (Constant P): Straight line that passes through the origin with a positive slope. d. P versus V (Constant T): Hyperbola, passing through the first and third quadrants. e. P versus 1/V (Constant T): Straight line that passes through the origin and has a positive slope. f. PV/T versus P (Constant n, R): Horizontal straight line parallel to the P-axis (x-axis).

Step by step solution

01

Qualitative Graph for PV versus V (Constant T)

Since T is constant, multiplying P by V will keep the value constant as well. Therefore, the graph of PV versus V will be a horizontal straight line parallel to the x-axis (V-axis). #Step 2: Graph of P versus T with constant V#
02

Qualitative Graph for P versus T (Constant V)

Using the Ideal Gas Law (PV= nRT), we rearrange the equation to get P=(nR/V)T. Since V is constant and nR is constant, it results in a linear relationship between P and T. The graph of P versus T will be a straight line that passes through the origin and has a positive slope. #Step 3: Graph of T versus V with constant P#
03

Qualitative Graph for T versus V (Constant P)

Rearrange the Ideal Gas Law to solve for T: T= PV/nR. Since P is constant, the relationship between T and V becomes linear. Therefore, the graph of T versus V will be a straight line that passes through the origin and has a positive slope. #Step 4: Graph of P versus V with constant T#
04

Qualitative Graph for P versus V (Constant T)

The Ideal Gas Law can be rewritten as P = nRT/V. With constant T and the product of nR also being constant, there will be an inverse relationship between P and V. In other words, as V increases, P will decrease. The graph of P versus V will be a hyperbola, passing through the first and third quadrants. #Step 5: Graph of P versus 1/V with constant T#
05

Qualitative Graph for P versus 1/V (Constant T)

Rearrange the Ideal Gas Law to get P=nRT/V. By replacing 1/V with X, we can see that the relationship between P and 1/V is linear (since nRT is constant), with P = nRTX. The graph of P versus 1/V will be a straight line passing through the origin and has a positive slope. #Step 6: Graph of PV/T versus P#
06

Qualitative Graph for PV/T versus P (Constant n, R)

From the Ideal Gas Law, we know that PV=nRT. Dividing both sides of the equation by T gives PV/T = nR. Since n and R are constants, the graph of PV/T versus P will also be a horizontal straight line parallel to the P-axis (x-axis).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider separate \(1.0\) -\(\mathrm{L}\) samples of \(\mathrm{He}(g)\) and \(\mathrm{UF}_{6}(g),\) both at \(1.00\) atm and containing the same number of moles. What ratio of temperatures for the two samples would produce the same root mean square velocity?

In the presence of nitric acid, \(UO\) \(^{2+}\) undergoes a redox process. It is converted to \(\mathrm{UO}_{2}^{2+}\) and nitric oxide (NO) gas is produced according to the following unbalanced equation: $$\begin{aligned}\mathrm{H}^{+}(a q)+\mathrm{NO}_{3}^{-}(a q)+\mathrm{UO}^{2 *}(a q) & \longrightarrow \\\\\mathrm{NO}(g)+& \mathrm{UO}_{2}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \end{aligned}$$ If \(2.55 \times 10^{2} \mathrm{mL} \mathrm{NO}(g)\) is isolated at \(29^{\circ} \mathrm{C}\) and \(1.5 \mathrm{atm}\), what amount (moles) of \(UO\) \(^{2+}\) was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)

Helium is collected over water at \(25^{\circ} \mathrm{C}\) and 1.00 atm total pressure. What total volume of gas must be collected to obtain \(0.586 \mathrm{g}\) helium? (At \(25^{\circ} \mathrm{C}\) the vapor pressure of water is 23.8 torr.)

A bicycle tire is filled with air to a pressure of \(75\) psi at a temperature of \(19^{\circ} \mathrm{C}\). Riding the bike on asphalt on a hot day increases the temperature of the tire to \(58^{\circ} \mathrm{C}\). The volume of the tire increases by \(4.0 \% .\) What is the new pressure in the bicycle tire?

Consider separate \(1.0-\mathrm{L}\) gaseous samples of \(\mathrm{He}, \mathrm{N}_{2},\) and \(\mathrm{O}_{2}\) all at \(\mathrm{STP}\) and all acting ideally. Rank the gases in order of increasing average kinetic energy and in order of increasing average velocity.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free