Some ionic compounds contain a mixture of different charged cations. For example, wüstite is an oxide that contains both \(\mathrm{Fe}^{2+}\) and \(\mathrm{Fe}^{3+}\) cations and has a formula of \(\mathrm{Fe}_{0.950} \mathrm{O}_{1.00}\). Calculate the fraction of iron ions present as \(\mathrm{Fe}^{3+} .\) What fraction of the sites normally occupied by \(\mathrm{Fe}^{2+}\) must be vacant in this solid?

Short Answer

Expert verified
The fraction of iron ions present as \(\mathrm{Fe}^{3+}\) is \(x = 0\) (0%), which means all iron ions are \(\mathrm{Fe}^{2+}\) ions. The fraction of vacant sites in the wüstite is \(0.050\) (5% of the sites normally occupied by \(\mathrm{Fe}^{2+}\)).

Step by step solution

01

Define variables

Let the fraction of ions as \(\mathrm{Fe}^{3+}\) be \(x\). So, the fraction of \(\mathrm{Fe}^{2+}\) ions will be \((1-x)\), since the total fraction of iron ions present in the wüstite is \(\mathrm{Fe}_{0.950}\).
02

Write the charge balance equation

Considering the charge balance, the sum of positive charges should be equal to the sum of negative charges: Positive charges from \(\mathrm{Fe}^{2+}\) ions: \((1 - x) \times 2\mathrm{e}\) Positive charges from \(\mathrm{Fe}^{3+}\) ions: \(x \times 3\mathrm{e}\) Negative charges from \(\mathrm{O}^{2-}\) ions: \(1.00 \times 2\mathrm{e}\) So, the equation for charge balance is: \((1 - x) \times 2\mathrm{e} + x \times 3\mathrm{e} = 2\mathrm{e}\)
03

Solve the charge balance equation for \(x\)

Simplify the equation: \(2\mathrm{e} - 2x\mathrm{e} + 3x\mathrm{e} = 2\mathrm{e}\) Combine the terms with \(x\): \(e(2 - 2x + 3x) = 2\mathrm{e}\) Dividing both sides by \(\mathrm{e}\): \(2 - 2x + 3x = 2\) Now solve for \(x\): \(x = 2 - 2 = 0\) So, the fraction of iron ions present as \(\mathrm{Fe}^{3+}\) is \(x = 0\).
04

Calculate the fraction of vacant sites

Since we know there are no \(\mathrm{Fe}^{3+}\) ions in the wüstite, all the iron ions are \(\mathrm{Fe}^{2+}\). So, the fraction of \(\mathrm{Fe}^{2+}\) ions is 0.950 (or 95%). To find out the fraction of vacant sites, we can subtract this value from the total possible sites for \(\mathrm{Fe}^{2+}\), which is 1, as all sites can either be occupied by \(\mathrm{Fe}^{2+}\) or vacant. Fraction of vacant sites = Total sites possible for \(\mathrm{Fe}^{2+}\) - Fraction of \(\mathrm{Fe}^{2+}\) Fraction of vacant sites = \(1 - 0.950 = 0.050\) (or 5%) So, 5% of the sites normally occupied by \(\mathrm{Fe}^{2+}\) must be vacant in this solid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Charge Balance Equation
In chemistry, particularly when dealing with ionic compounds such as wüstite, the concept of the charge balance equation is crucial. It states that the total positive charge in a compound must equal the total negative charge, maintaining electrical neutrality.

The charge balance equation is written by equating the sum of charges from all cations to the sum of charges from all anions. For instance, in wüstite, iron can be present as \(\mathrm{Fe}^{2+}\) and \(\mathrm{Fe}^{3+}\), while oxygen is present as \(\mathrm{O}^{2-}\). If \(x\) is the fraction of \(\mathrm{Fe}^{3+}\) ions, the charge balance equation is set up by multiplying the fraction of each type of iron ion by its respective charge, and this sum should be equal to the charge from oxygen ions.

Understanding this equilibrium allows us to calculate the proportion of different ions in the compound. If an error is identified in the step-by-step solution provided, such as a wrong calculation or misinterpretation of the charge balance, correcting it would be crucial for identifying the correct composition of the ionic compound.
Deciphering the Cation Mixture
Ionic compounds can have a mixture of cations with different charges. When solving problems involving such cation mixtures, it's important to clearly define the variables representing the fraction of each cation type.

In the provided example of wüstite, which contains a mixture of \(\mathrm{Fe}^{2+}\) and \(\mathrm{Fe}^{3+}\), we start by assigning a variable to the fraction of one cation to express the other cation's fraction in relation to it. This understanding of the cation mixture is essential for further steps, such as applying the charge balance equation or determining the stoichiometry of the compound.

Focusing on the step-by-step solution, ensure that the appropriate cation types and their fractions are accurately considered. Misunderstanding the cation mixture can lead to incorrect conclusions about the compound's structure or the calculation of vacant sites.
Applying Stoichiometry to Ionic Compounds
Stoichiometry is a branch of chemistry that involves calculating the amounts of reactants and products in chemical reactions. For ionic compounds, stoichiometry helps determine the proportions of each ion necessary to achieve neutrality.

The example given on wüstite's composition requires stoichiometric calculations to understand the ratio of iron to oxygen ions, and infer further details like the fraction of vacant sites. By understanding the ratio of ions and the overall formula of the compound, we can utilize stoichiometry to deduce not only the percentage of each type of cation but also the extent of vacancies or other defects within the crystal structure.

Be mindful of potential errors in solving stoichiometry problems, such as incorrect coefficients or misapplication of the mole concept. Aligning stoichiometry with the charge balance and recognizing the nature of the cation mixture ensures accurate and comprehensive solutions to such textbook exercises.

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