Carbon tetrachloride, \(\mathrm{CCl}_{4},\) has a vapor pressure of 213 torr at \(40 .^{\circ} \mathrm{C}\) and 836 torr at \(80 .^{\circ} \mathrm{C} .\) What is the normal boiling point of \(\mathrm{CCl}_{4} ?\)

Short Answer

Expert verified
The normal boiling point of \(\mathrm{CCl}_{4}\) is approximately \(77.20^{\circ}\mathrm{C}\).

Step by step solution

01

(Step 1: Write down the Clausius-Clapeyron equation)

The Clausius-Clapeyron equation relates the vapor pressure of a substance with its temperature: \[\ln\frac{P_2}{P_1} = -\frac{L}{R}\left(\frac{1}{T_2} - \frac{1}{T_1}\right)\] where: - \(P_1\) and \(P_2\) are the vapor pressures at temperatures \(T_1\) and \(T_2\), respectively - \(L\) is the molar heat of vaporization - \(R\) is the ideal gas constant (\(8.314\, \mathrm{J/mol \cdot K}\))
02

(Step 2: Convert temperatures to Kelvin)

Since the given temperatures are in Celsius, we need to convert them to Kelvin by adding 273.15: \[T_1 = 40^{\circ}\mathrm{C} + 273.15 = 313.15\,\mathrm{K}\] \[T_2 = 80^{\circ}\mathrm{C} + 273.15 = 353.15\,\mathrm{K}\]
03

(Step 3: Solve for the molar heat of vaporization L)

Given the vapor pressures and temperatures, we can plug the values into the Clausius-Clapeyron equation and solve for the molar heat of vaporization: \[\ln\frac{836}{213} = -\frac{L}{8.314}\left(\frac{1}{353.15} - \frac{1}{313.15}\right)\] Calculate \(L\): \[L = -8.314\,\frac{\ln\frac{836}{213}}{\frac{1}{353.15} - \frac{1}{313.15}} = 2.985 \times 10^{4}\, \mathrm{J/mol}\]
04

(Step 4: Solve for the normal boiling point temperature)

We can rearrange the Clausius-Clapeyron equation, substituting the vapor pressure at the normal boiling point (760 torr), to isolate the temperature: \[\ln\frac{760}{213} = -\frac{2.985 \times 10^{4}}{8.314}\left(\frac{1}{T_{nbp}} - \frac{1}{313.15}\right)\] Now we can solve for the normal boiling point temperature, \(T_{nbp}\): \[T_{nbp} = \frac{1}{\frac{1}{313.15} - \frac{8.314}{2.985 \times 10^{4}}\ln\frac{760}{213}} = 350.35\,\mathrm{K}\]
05

(Step 5: Convert the normal boiling point temperature back to Celsius)

Finally, convert the normal boiling point temperature, \(T_{nbp}\), from Kelvin to Celsius: \[T_{nbp} = 350.35 - 273.15 = 77.20^{\circ}\mathrm{C}\] Therefore, the normal boiling point of \(\mathrm{CCl}_{4}\) is approximately \(77.20^{\circ}\mathrm{C}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vapor Pressure
Vapor pressure is a measure of a liquid's tendency to evaporate into a gas. It is the pressure exerted by the vapor when the liquid and vapor states are in equilibrium. At any given temperature, every liquid has a characteristic vapor pressure that increases as temperature rises, because more molecules have enough energy to overcome the liquid’s surface tension and escape into the gaseous state.

Understanding vapor pressure is crucial when studying the Clausius-Clapeyron equation because it's one of the key variables that correlate to temperature changes. In the exercise provided, we are given two vapor pressures at different temperatures which are then used to calculate the molar heat of vaporization and the normal boiling point of carbon tetrachloride.
Molar Heat of Vaporization
The molar heat of vaporization (\( L \)) is the amount of heat required to convert one mole of a liquid into vapor without a temperature change. It's a characteristic property that differs from substance to substance. This concept is at the heart of the Clausius-Clapeyron equation and plays a central role in determining how vapor pressure changes with temperature.

The step-by-step exercise exemplifies calculating the molar heat of vaporization for carbon tetrachloride by using the vapor pressures at two different temperatures. Knowing the molar heat of vaporization allows us to predict how a liquid will behave under various temperature conditions and is key in identifying the boiling point.
Normal Boiling Point
The normal boiling point of a liquid is the temperature at which its vapor pressure equals one atmosphere (101.325 kPa or 760 torr). At this point, vapor bubbles can form within the liquid, and it begins to transform into a gas (boil).

Using the Clausius-Clapeyron equation, the normal boiling point can be determined by setting the vapor pressure variable to the standard atmospheric pressure and solving for the temperature. In our exercise, we found the normal boiling point of carbon tetrachloride by using the molar heat of vaporization and the given vapor pressures at two specific temperatures. This temperature is crucial for applications involving boiling, distillation, and chemical reactions.
Temperature Conversion
Temperature conversion is necessary when using the Clausius-Clapeyron equation since it requires absolute temperature measurements in Kelvins (K). The Celsius (°C) to Kelvin conversion is one of the simplest temperature conversions, requiring only the addition or subtraction of 273.15.

In the textbook problem solution, the temperatures provided in Celsius needed to be converted to Kelvins for accurate inclusion in the Clausius-Clapeyron equation. Similarly, after finding the normal boiling point in Kelvins, the final step is to convert it back into Celsius to provide an understandable result relative to everyday temperature measurements. Proper temperature conversion avoids errors in calculations and ensures that the results are correct and meaningful.

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Most popular questions from this chapter

General Zod has sold Lex Luthor what Zod claims to be a new copper-colored form of kryptonite, the only substance that can harm Superman. Lex, not believing in honor among thieves, decided to carry out some tests on the supposed kryptonite. From previous tests, Lex knew that kryptonite is a metal having a specific heat capacity of \(0.082 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C}\) and a density of \(9.2 \mathrm{g} / \mathrm{cm}^{3}.\) Lex Luthor's first experiment was an attempt to find the specific heat capacity of kryptonite. He dropped a \(10 \mathrm{g} \pm 3 \mathrm{g}\) sample of the metal into a boiling water bath at a temperature of \(100.0^{\circ} \mathrm{C} \pm 0.2^{\circ} \mathrm{C} .\) He waited until the metal had reached the bath temperature and then quickly transferred it to \(100 \mathrm{g} \pm 3 \mathrm{g}\) of water that was contained in a calorimeter at an initial temperature of \(25.0^{\circ} \mathrm{C} \pm 0.2^{\circ} \mathrm{C} .\) The final temperature of the metal and water was \(25.2^{\circ} \mathrm{C} .\) Based on these results, is it possible to distinguish between copper and kryptonite? Explain. When Lex found that his results from the first experiment were inconclusive, he decided to determine the density of the sample. He managed to steal a better balance and determined the mass of another portion of the purported kryptonite to be \(4 \mathrm{g} \pm 1\) g. He dropped this sample into water contained in a 25-mL graduated cylinder and found that it displaced a volume of \(0.42 \mathrm{mL} \pm 0.02 \mathrm{mL} .\) Is the metal copper or kryptonite? Explain. Lex was finally forced to determine the crystal structure of the metal General Zod had given him. He found that the cubic unit cell contained four atoms and had an edge length of \(600 . \mathrm{pm} .\) Explain how this information enabled Lex to identify the metal as copper or kryptonite. Will Lex be going after Superman with the kryptonite or seeking revenge on General Zod? What improvements could he have made in his experimental techniques to avoid performing the crystal structure determination?

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