Suggest an explanation for the observations that ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), is completely miscible with water and that ethanethiol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{SH},\) is soluble only to the extent of \(1.5 \mathrm{g}\) per \(100 \mathrm{mL}\) of water.

Short Answer

Expert verified
Ethanol is completely miscible with water due to its ability to form strong hydrogen bonds with water molecules through its \( -OH \) group. Ethanethiol has limited solubility because its \( -SH \) group forms weaker hydrogen bonds with water and has a lower polarity compared to the \( -OH \) group in ethanol.

Step by step solution

01

Understand the Concept of Miscibility and Solubility

Miscibility refers to the ability of a liquid to mix with another liquid in any proportion without separating into two phases, resulting in a homogeneous solution. Solubility is the maximum amount of a substance that can be dissolved in a given quantity of solvent at a specified temperature. Both of these properties are influenced by the molecular structure of the substances involved and their intermolecular interactions with the solvent.
02

Analyze Intermolecular Forces in Ethanol and Water

Ethanol \( \mathrm{C}_{2}\mathrm{H}_{5} \mathrm{OH} \) and water both have hydroxyl groups (\(-OH\)) which are capable of forming strong hydrogen bonds. Due to the similar polarity and ability to form hydrogen bonds with water, ethanol is completely miscible with water.
03

Examine Ethanol and Ethanethiol Structures

The difference between ethanol and ethanethiol \( \mathrm{C}_{2}\mathrm{H}_{5} \mathrm{SH} \) is the functional group; ethanol has an hydroxyl group (\(-OH\)), while ethanethiol has a thiol group (\(-SH\)). Even though both groups can participate in hydrogen bonding, the bond strength and polarity differ.
04

Explain the Solubility of Ethanethiol

Ethanethiol's thiol group is less polar than ethanol's hydroxyl group and forms weaker hydrogen bonds with water. Additionally, the larger size and lower electronegativity of sulfur compared to oxygen result in weaker interactions with water. Therefore, ethanethiol has limited solubility in water (1.5 g per 100 mL), unlike ethanol which is completely miscible.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Bonding
Hydrogen bonding is a special type of dipole-dipole attraction that occurs between molecules, a powerful intermolecular force that significantly affects solubility and miscibility. It specifically involves a hydrogen atom that is bonded to an electronegative atom like oxygen, nitrogen, or fluorine. This hydrogen atom experiences an attraction to an unshared pair of electrons from an electronegative atom in a nearby molecule.

In the context of our exercise, ethanol (\( \text{C}_2\text{H}_5\text{OH} \) displays strong hydrogen bonding thanks to its hydroxyl \( -OH \) group. The attraction between the hydrogen atom of one ethanol molecule and the oxygen atom of another ethanol molecule OR an adjacent water molecule is strong enough to allow ethanol to mix thoroughly with water, creating a homogeneous solution - hence, full miscibility.
Intermolecular Forces
Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules or ions). These forces are relatively weak compared to the strong intramolecular forces, such as covalent bonds, within a molecule. Intermolecular forces are responsible for various physical properties of substances, such as boiling and melting points, vapor pressure, and, in our case, solubility and miscibility.

There are several types of intermolecular forces, with van der Waals forces encompassing London dispersion forces, dipole-dipole interactions, and hydrogen bonds. In comparing ethanol and ethanethiol, the difference in their intermolecular attractions with water molecules is key to understanding why ethanol is completely miscible with water, while ethanethiol has limited solubility. The weaker van der Waals forces in ethanethiol cannot compete with the stronger hydrogen bonding of ethanol, which results in their different behaviors in water.
Polarity of Molecules
The polarity of a molecule is a measure of how evenly it shares electrons between the atoms that make up the molecule. If the atoms share electrons unequally, the molecule has a net dipole moment, making it polar. For substances to dissolve in each other, it is generally necessary that they have similar polarities (like dissolves like).

Ethanol and water both have strong polar characters due to their -OH groups, which allows them to interact through hydrogen bonds. In contrast, ethanethiol's -SH group does have some polarity but it's not as strong as the ethanol's polar -OH group. As a result, it's less effective in interacting with the polar water molecules, which clarifies why it has a much lower solubility in water compared to ethanol's complete miscibility.
Functional Groups in Organic Chemistry
Organic molecules contain functional groups, which are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. They are the sites of chemical reactivity. Functional groups like alcohols (\( -OH \) groups) and thiols (\( -SH \) groups) influence the polarity and intermolecular bonding capabilities of organic compounds.

Ethanol contains an alcohol functional group which is very polar due to the electronegativity difference between the oxygen and the hydrogen atom. This characteristic gives ethanol a high level of miscibility with water. On the other hand, ethanethiol contains a thiol group that is less polar, which results in weaker intermolecular attractions with water and thus less solubility. The contrast in the behavior of these two functional groups in response to water is a clear demonstration of the importance of functional groups in determining the physical and chemical properties of organic compounds.

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Most popular questions from this chapter

The Henry's law constant for \(\mathrm{CO}_{2}\) is \(3.4 \times 10^{-2} \mathrm{M} / \mathrm{atm}\) at \(25^{\circ} \mathrm{C}\). Assuming ideal solution behavior, what pressure of carbon dioxide is needed to maintain a \(\mathrm{CO}_{2}\) concentration of \(0.10 \mathrm{M}\) in a can of lemon-lime soda?

Explain why the ions \(\mathrm{Na}^{+}\) and \(\mathrm{Cl}^{-}\) are strongly solvated in water but not in hexane, a solvent composed of nonpolar molecules.

Calculate the mole fraction of each solute and solvent: (a) \(0.710 \mathrm{kg}\) of sodium carbonate (washing soda), \(\mathrm{Na}_{2} \mathrm{CO}_{3},\) in \(10.0 \mathrm{kg}\) of water \(-\) a saturated solution at \(0^{\circ} \mathrm{C}\) (b) \(125 \mathrm{g}\) of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in \(275 \mathrm{g}\) of water \(-\) a mixture used to make an instant ice pack (c) \(25 \mathrm{g}\) of \(\mathrm{Cl}_{2}\) in \(125 \mathrm{g}\) of dichloromethane, \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) (d) \(0.372 \mathrm{g}\) of tetrahydropyridine, \(\mathrm{C}_{5} \mathrm{H}_{9} \mathrm{N},\) in \(125 \mathrm{g}\) of chloroform, \(\mathrm{CHCl}_{3}\)

Solutions of hydrogen in palladium may be formed by exposing Pd metal to \(\mathrm{H}_{2}\) gas. The concentration of hydrogen in the palladium depends on the pressure of \(\mathrm{H}_{2}\) gas applied, but in a more complex fashion than can be described by Henry's law. Under certain conditions, 0.94 g of hydrogen gas is dissolved in 215 g of palladium metal (solution density \(=10.8 \mathrm{g} \mathrm{cm}^{3}\) ). (a) Determine the molarity of this solution. (b) Determine the molality of this solution. (c) Determine the percent by mass of hydrogen atoms in this solution.

The vapor pressure of methanol, \(\mathrm{CH}_{3} \mathrm{OH}\), is 94 torr at \(20^{\circ} \mathrm{C}\). The vapor pressure of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), is 44 torr at the same temperature. (a) Calculate the mole fraction of methanol and of ethanol in a solution of \(50.0 \mathrm{g}\) of methanol and \(50.0 \mathrm{g}\) of ethanol. (b) Ethanol and methanol form a solution that behaves like an ideal solution. Calculate the vapor pressure of methanol and of ethanol above the solution at \(20^{\circ} \mathrm{C}\). (c) Calculate the mole fraction of methanol and of ethanol in the vapor above the solution.

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