When ammonium chloride is added to water and stirred, it dissolves spontaneously and the resulting solution feels cold. Without doing any calculations, deduce the signs of \(\Delta G, \Delta H,\) and \(\Delta S\) for this process, and justify your choices.

Short Answer

Expert verified
∆G is negative due to the spontaneous nature of the dissolution, ∆H is positive since the process is endothermic and absorbs heat, and ∆S is positive because the solid salt disperses in water, increasing disorder.

Step by step solution

01

Understanding ∆G (Gibbs Free Energy Change)

The spontaneous nature of ammonium chloride dissolving in water indicates that the process occurs without external influence. For a process to occur spontaneously, the change in Gibbs Free Energy (∆G) must be negative. Therefore, ∆G is negative for this dissolution.
02

Determining the Sign of ∆H (Enthalpy Change)

The fact that the solution feels cold to the touch suggests that the dissolving process is endothermic; it absorbs heat from the surroundings. Therefore, the change in enthalpy (∆H) is positive for the dissolution of ammonium chloride in water.
03

Inferring the Sign of ∆S (Entropy Change)

When ammonium chloride dissolves, it goes from an orderly solid state to a more disordered state in solution, which means that the entropy (∆S) increases. So, the change in entropy (∆S) is positive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs Free Energy, represented as \( \Delta G \), is a thermodynamic property that can predict the direction of chemical processes. To grasp its significance, it helps to remember that all systems tend toward minimal free energy. In simple terms, imagine rolling a ball downhill; just like the ball naturally rolls toward the lowest point, a reaction naturally proceeds toward the lowest free energy. To facilitate understanding, consider this analogy when pondering on Gibbs Free Energy.
For a process to happen on its own—termed 'spontaneous'—the \( \Delta G \) must be negative. When \( \Delta G \) is negative, it indicates that the system has lost free energy, and the process can proceed without adding energy from outside sources. This mirrors the exercise where ammonium chloride dissolved in water signified a spontaneous process because the dissolution led to a decrease in free energy, hence a negative \( \Delta G \).
This concept becomes essential in chemistry because it bridges the gap between the microscopic behavior of molecules and the macroscopic observation of chemical reactions. Understanding \( \Delta G \) helps students make thermodynamic predictions about reaction spontaneity based on changes in enthalpy and entropy, without the need for experiments.
Enthalpy Change
Enthalpy change, denoted as \( \Delta H \), reflects the total heat content within a system and is associated with chemical reactions occurring at constant pressure. This term might sound abstract, but thinking of it as a 'heat account' for chemical processes can make it more tangible. When you add heat to the system, it's like depositing money into the account—the overall enthalpy increases, indicating a positive \( \Delta H \). Conversely, when the system releases heat, it's as if it's withdrawing heat, signifying a negative \( \Delta H \).
In the context of the provided exercise, the solution feels cold to the touch, which is a telltale sign the process is endothermic (it requires heat from the surroundings). This bit of sensory information tells us that \( \Delta H \) is positive for the dissolution of ammonium chloride. Often in chemistry, the enthalpy change relates directly to the energy required to break and form bonds during a reaction, a concept central to students' understanding of chemical reaction energetics.
Entropy Change
Entropy change, symbolized as \( \Delta S \), represents the change in disorder within a system. A straightforward way to picture entropy is to imagine a room full of scattered toys compared to the same room with toys neatly arranged. The more disordered room has higher entropy. Therefore, in chemical terms, an increase in entropy (\

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Most popular questions from this chapter

Consider two processes: sublimation of \(\mathrm{I}_{2}(s)\) and melting of \(\mathrm{I}_{2}(\mathrm{s})\) (Note: the latter process can occur at the same temperature but somewhat higher pressure). \(\mathrm{I}_{2}(s) \longrightarrow \mathrm{I}_{2}(g)\) \(\mathrm{I}_{2}(s) \longrightarrow \mathrm{I}_{2}(l)\) Is \(\Delta S\) positive or negative in these processes? In which of the processes will the magnitude of the entropy change be greater?

Predict the sign of the entropy change for the following processes. Give a reason for your prediction. (a) \(\mathrm{Pb}^{2+}(a q)+\mathrm{S}^{2-}(a q) \longrightarrow \mathrm{PbS}(s)\) (b) \(2 \mathrm{Fe}(s)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{Fe}_{2} \mathrm{O}_{2}(s)\) (c) \(2 \mathrm{C}_{6} \mathrm{H}_{14}(l)+19 \mathrm{O}_{2}(g) \longrightarrow 14 \mathrm{H}_{2} \mathrm{O}(g)+12 \mathrm{CO}_{2}(g)\)

From the following information, determine \(\Delta S^{\circ}\) for the following: \(\mathrm{N}(g)+\mathrm{O}(g) \longrightarrow \mathrm{NO}(g) \quad \Delta S^{\circ}=?\) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}(g) \quad \Delta S^{\circ}=24.8 \mathrm{J} / \mathrm{K}\) \(\mathrm{N}_{2}(g) \longrightarrow 2 \mathrm{N}(g) \quad \Delta S^{\circ}=115.0 \mathrm{J} / \mathrm{K}\) \(\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{O}(g) \quad \Delta S^{\circ}=117.0 \mathrm{J} / \mathrm{K}\)

By calculating \(\Delta S_{\text {univ }}\) at each temperature, determine if the melting of 1 mole of \(\mathrm{NaCl}(s)\) is spontaneous at 500 \(^{\circ} \mathrm{C}\) and at \(700^{\circ} \mathrm{C}\). $$S_{\mathrm{NaCl}(s)}^{\circ}=72.11 \frac{\mathrm{J}}{\mathrm{mol} \cdot \mathrm{K}} \quad S_{\mathrm{NaCl}(l)}^{\circ}=95.06 \frac{\mathrm{J}}{\mathrm{mol} \cdot \mathrm{K}} \quad \Delta H_{\mathrm{fusion}}^{\circ}=27.95 \mathrm{kJ} / \mathrm{mol}$$ What assumptions are made about the thermodynamic information (entropy and enthalpy values) used to solve this problem?

A helium-filled balloon spontaneously deflates overnight as He atoms diffuse through the wall of the balloon. Describe the redistribution of matter and/or energy that accompanies this process.

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