Chapter 13: Problem 3
If a reaction is reversible, when can it be said to have reached equilibrium?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 13: Problem 3
If a reaction is reversible, when can it be said to have reached equilibrium?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeThe equilibrium constant \(\left(K_{c}\right)\) for this reaction is 5.0 at a given temperature. \(\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{CO}_{2}(g)+\mathrm{H}_{2}(g)\) (a) On analysis, an equilibrium mixture of the substances present at the given temperature was found to contain 0.20 mol of \(\mathrm{CO}, 0.30\) mol of water vapor, and \(0.90 \mathrm{mol}\) of \(\mathrm{H}_{2}\) in a liter. How many moles of \(\mathrm{CO}_{2}\) were there in the equilibrium mixture? (b) Maintaining the same temperature, additional \(\mathrm{H}_{2}\) was added to the system, and some water vapor was removed by drying. A new equilibrium mixture was thereby established containing 0.40 mol of \(\mathrm{CO}, 0.30\) mol of water vapor, and 1.2 mol of \(\mathrm{H}_{2}\) in a liter. How many moles of \(\mathrm{CO}_{2}\) were in the new equilibrium mixture? Compare this with the quantity in part (a), and discuss whether the second value is reasonable. Explain how it is possible for the water vapor concentration to be the same in the two equilibrium solutions even though some vapor was removed before the second equilibrium was established.
What property of a reaction can we use to predict the effect of a change in temperature on the value of an equilibrium constant?
Write the mathematical expression for the reaction quotient, \(Q_{c}\) for each of the following reactions: (a) \(\mathrm{CH}_{4}(\mathrm{g})+\mathrm{C}_{2}(\mathrm{g})=\mathrm{CH}_{3} \mathrm{Cl}(\mathrm{g})+\mathrm{HCl}(g)\) (b) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)=2 \mathrm{NO}(g)\) (c) \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{SO}_{3}(g)\) (d) \(\operatorname{BaSO}_{3}(s)=\operatorname{BaO}(s)+\operatorname{SO}_{2}(g)\) (e) \(\mathrm{P}_{4}(g)+5 \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{P}_{4} \mathrm{O}_{10}(s)\) (f) \(\operatorname{Br}_{2}(g)=2 \operatorname{Br}(g)\) (g) \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(I)\) (h) \(\operatorname{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(s)=\mathrm{CuSO}_{4}(s)+5 \mathrm{H}_{2} \mathrm{O}(g)\)
Calculate the value of the equilibrium constant \(K_{P}\) for the reaction \(2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{NOCl}(g)\) from these equilibrium pressures: \(\mathrm{NO}, 0.050 \mathrm{atm} ; \mathrm{Cl}_{2}, 0.30\) atm; \(\mathrm{NOCl}, 1.2 \mathrm{atm}\)
Explain why there may be an infinite number of values for the reaction quotient of a reaction at a given temperature but there can be only one value for the equilibrium constant at that temperature.
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