What property of a reaction can we use to predict the effect of a change in temperature on the value of an equilibrium constant?

Short Answer

Expert verified
The enthalpy change (ΔH) of a reaction is the property used to predict the effect of a change in temperature on the value of an equilibrium constant (K).

Step by step solution

01

Understanding Chemical Equilibrium and Temperature

The property that can predict the effect of a change in temperature on the value of an equilibrium constant is the enthalpy change (ΔH) of the reaction. An equilibrium reaction follows Le Chatelier's Principle, which states that a system at equilibrium will adjust itself to counteract the effect of a change. If the reaction is exothermic (ΔH is negative), an increase in temperature will result in a decrease in the equilibrium constant (K), shifting the equilibrium position to the left (towards reactants). Conversely, for an endothermic reaction (ΔH is positive), an increase in temperature will increase K, shifting the equilibrium position to the right (towards products).
02

Using the van't Hoff Equation

The van't Hoff equation provides a quantitative relationship between the change in temperature and the equilibrium constant. It is expressed as: \( \frac{d\ln K}{dT} = \frac{\Delta H}{RT^2} \), where \( K \) is the equilibrium constant, \( T \) is the temperature in Kelvin, \( R \) is the universal gas constant, and \( \Delta H \) is the enthalpy change of the reaction. This equation allows for the prediction of how K will change with temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
When studying dynamic chemical systems, Le Chatelier's Principle is a crucial concept to grasp. It posits that if an external condition is altered on a chemical system at equilibrium, the equilibrium will shift to counteract the change. Imagine a seesaw balanced evenly; if weight is added to one side, the seesaw will tilt to that side in response. Similarly, if the temperature of a reaction in equilibrium changes, the system will adjust its position to lessen the impact of that change.

If the reaction releases heat (exothermic), heating the system will cause a shift towards the reactants to absorb the excess heat. On the other hand, if the reaction absorbs heat (endothermic), an increase in temperature will shift the equilibrium towards the products, as it favors the absorption of heat. Understanding this concept aids in predicting how alterations in temperature will affect the balance between reactants and products in a chemical equilibrium.
Enthalpy Change
Enthalpy change, represented as \( \Delta H \), is an essential part of thermodynamics and indicates the heat change within a reaction at constant pressure. Think of it as a measure of energy absorbed or released when a reaction occurs. In the context of equilibrium, if \( \Delta H \) is negative, we're looking at an exothermic reaction that releases heat into the surroundings. In contrast, a positive \( \Delta H \) signifies an endothermic reaction, which requires heat from its environment to proceed.

The sign and magnitude of \( \Delta H \) play pivotal roles when we apply Le Chatelier's Principle to temperature changes. They tell us whether the reaction will favor the formation of products or reactants as the temperature varies.
Van't Hoff Equation
Delving into the quantitative side, the van't Hoff equation serves as a mathematical expression that correlates the effect of temperature on the equilibrium constant of a reaction. The equation is formulated as \[ \frac{d\ln K}{dT} = \frac{\Delta H}{RT^2} \], where \( K \) is the equilibrium constant, \( T \) is the absolute temperature in Kelvin, \( R \) is the universal gas constant, and \( \Delta H \) is the enthalpy change. This equation essentially allows us to calculate how \( K \) will vary when the temperature changes.

To put it in perspective, if we have an exothermic reaction, the equilibrium constant will decrease as the temperature goes up — consistent with Le Chatelier's Principle. Conversely, for an endothermic reaction, an increase in temperature will increase the equilibrium constant, indicating a shift towards more products.
Equilibrium Constant
Lastly, the equilibrium constant, symbolized by \( K \), is a value that reflects the ratio of the concentrations of the products to the reactants at chemical equilibrium, each raised to the power of their stoichiometric coefficients. It's a snapshot of the state of the reaction when the rates of the forward and reverse reactions are equal, meaning no net change in the amounts of reactants and products.

Given the importance of temperature revealed by Le Chatelier's Principle, it becomes clear that \( K \) is not just a constant in the literary sense but is dependent on temperature. Higher temperatures will shift \( K \) for endothermic reactions, while lower temperatures favor exothermic ones. Understanding this relationship and how to calculate these changes using the van't Hoff equation empowers students to predict and explain the outcomes of temperature changes on chemical systems at equilibrium.

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Most popular questions from this chapter

Write the mathematical expression for the reaction quotient, \(Q_{c}\) for each of the following reactions: (a) \(\mathrm{CH}_{4}(\mathrm{g})+\mathrm{C}_{2}(\mathrm{g})=\mathrm{CH}_{3} \mathrm{Cl}(\mathrm{g})+\mathrm{HCl}(g)\) (b) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)=2 \mathrm{NO}(g)\) (c) \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{SO}_{3}(g)\) (d) \(\operatorname{BaSO}_{3}(s)=\operatorname{BaO}(s)+\operatorname{SO}_{2}(g)\) (e) \(\mathrm{P}_{4}(g)+5 \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{P}_{4} \mathrm{O}_{10}(s)\) (f) \(\operatorname{Br}_{2}(g)=2 \operatorname{Br}(g)\) (g) \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(I)\) (h) \(\operatorname{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}(s)=\mathrm{CuSO}_{4}(s)+5 \mathrm{H}_{2} \mathrm{O}(g)\)

Water gas, a mixture of \(\mathrm{H}_{2}\) and \(\mathrm{CO}\), is an important industrial fuel produced by the reaction of steam with red hot coke, essentially pure carbon. (a) Write the expression for the equilibrium constant for the reversible reaction \(\mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{CO}(g)+\mathrm{H}_{2}(g) \quad \Delta H=131.30 \mathrm{kJ}\) (b) What will happen to the concentration of each reactant and product at equilibrium if more \(C\) is added? (c) What will happen to the concentration of each reactant and product at equilibrium if \(\mathrm{H}_{2} \mathrm{O}\) is removed? (d) What will happen to the concentration of each reactant and product at equilibrium if CO is added? (e) What will happen to the concentration of each reactant and product at equilibrium if the temperature of the system is increased?

A reaction is represented by this equation: \(2 \mathrm{W}(a q) \rightleftharpoons \mathrm{X}(a q)+2 \mathrm{Y}(a q) \quad K_{c}=5 \times 10^{-4}\) (a) Write the mathematical expression for the equilibrium constant. (b) Using concentrations of \(\leq 1 M,\) identify two sets of concentrations that describe a mixture of \(\mathrm{W}, \mathrm{X},\) and \(\mathrm{Y}\) at equilibrium.

The following reaction occurs when a burner on a gas stove is lit: \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\)

A solution is saturated with silver sulfate and contains excess solid silver sulfate: \(\mathrm{Ag}_{2} \mathrm{SO}_{4}(s) \rightleftharpoons 2 \mathrm{Ag}^{+}(a q)+\mathrm{SO}_{4}^{2-}(a q)\) A small amount of solid silver sulfate containing a radioactive isotope of silver is added to this solution. Within a few minutes, a portion of the solution phase is sampled and tests positive for radioactive \(\mathrm{Ag}^{+}\) ions. Explain this observation.

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