Analysis of the gases in a sealed reaction vessel containing \(\mathrm{NH}_{3}, \mathrm{N}_{2},\) and \(\mathrm{H}_{2}\) at equilibrium at \(400^{\circ} \mathrm{C}\) established the concentration of \(\mathrm{N}_{2}\) to be \(1.2 \mathrm{M}\) and the concentration of \(\mathrm{H}_{2}\) to be \(0.24 \mathrm{M}\). \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g) \quad K_{c}=0.50\) at \(400^{\circ} \mathrm{C}\) Calculate the equilibrium molar concentration of \(\mathrm{NH}_{3}\)

Short Answer

Expert verified
\( [NH_3] \approx 0.091 M \)

Step by step solution

01

Establish the reaction and the equilibrium expression

Write down the balanced chemical equation for the reaction and the expression for the equilibrium constant, Kc. Reaction: \( N_2(g) + 3 H_2(g) \rightleftharpoons 2 NH_3(g) \) Equilibrium expression: \( K_c = \frac{[NH_3]^2}{[N_2][H_2]^3} \)
02

Substitute the given concentrations into the equilibrium expression

Substitute the given concentrations of \( N_2 \) and \( H_2 \) into the equilibrium expression and solve for the concentration of \( NH_3 \).Given: \( [N_2] = 1.2 M, [H_2] = 0.24 M, K_c = 0.50 \)Substituted expression: \( 0.50 = \frac{[NH_3]^2}{(1.2)(0.24)^3} \)
03

Solve for the concentration of \( NH_3 \)

Isolate the concentration of \( NH_3 \) and solve for its value. Rearrange the equation to get: \( [NH_3]^2 = K_c \times [N_2] \times [H_2]^3 \)Calculate: \( [NH_3]^2 = 0.50 \times 1.2 \times (0.24)^3 \)
04

Calculate the molar concentration of \( NH_3 \)

Take the square root of both sides to find the concentration of \( NH_3 \).\( [NH_3] = \sqrt{0.50 \times 1.2 \times (0.24)^3} = \sqrt{0.50 \times 1.2 \times 0.013824} = \sqrt{0.0082944} \approx 0.091 M \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
Understanding the equilibrium constant, often represented as Kc, is crucial in the study of chemical reactions that have reached a state of balance. At an established temperature, the equilibrium constant is a value that quantifies the ratio of the concentration of products to the concentration of reactants, each raised to the power of their stoichiometric coefficients in a balanced equation.

In the given exercise, the equilibrium constant for the reaction between N2 and H2 forming NH3 is provided as Kc = 0.50 at 400°C. The key to understanding this is recognizing that a Kc value provides insight into the favorability of the forward or reverse reactions. If the value of Kc is high, the formation of products is favored, and if it is low, the reactants are favored.

To apply this concept to the problem, you would set up the equilibrium constant expression using the molar concentrations of the gases involved (see the given formula in the solution). It is this relationship that allows us to determine the unknown concentration of NH3, based on the equilibrium constant and the concentrations of N2 and H2.
Molar Concentration
Molar concentration, symbolized as M and also known as molarity, is a measure of the concentration of a solute in a solution. It represents the moles of a substance per liter of solution. This concept is essential in stoichiometry and calculations involving chemical reactions because it allows chemists to quantify the amount of reactants and products.

In the exercise, you're provided with the molar concentrations of nitrogen gas, N2, (1.2 M) and hydrogen gas, H2, (0.24 M). These values become the input you need to calculate the equilibrium concentration of ammonia, NH3. Accuracy in measuring and understanding molar concentrations is key for correctly solving many chemical equilibrium problems.

To find the unknown concentration of NH3, the molar concentrations of the known substances are substituted into the equilibrium expression, which illustrates the importance of molar concentration in determining the position of equilibrium.
Reaction Quotient
The reaction quotient, denoted Qc, is akin to the equilibrium constant, Kc, but for a reaction that has not necessarily reached equilibrium. It is calculated using the same formula as Kc but with the initial concentrations of the reactants and products. Qc is instrumental in predicting the direction the reaction will shift to reach equilibrium.

If Qc is less than Kc, the reaction will proceed in the forward direction to produce more products. Conversely, if Qc is greater than Kc, the reaction will shift in the reverse direction to produce more reactants.

In the context of our exercise, once the reaction reaches equilibrium, Qc equals Kc, allowing for the system's equilibrium concentrations to be calculated. This condition is crucial to solving for NH3's concentration and provides the bridge between the initial reaction conditions and the established equilibrium state.

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Most popular questions from this chapter

A solution is saturated with silver sulfate and contains excess solid silver sulfate: \(\mathrm{Ag}_{2} \mathrm{SO}_{4}(s) \rightleftharpoons 2 \mathrm{Ag}^{+}(a q)+\mathrm{SO}_{4}^{2-}(a q)\) A small amount of solid silver sulfate containing a radioactive isotope of silver is added to this solution. Within a few minutes, a portion of the solution phase is sampled and tests positive for radioactive \(\mathrm{Ag}^{+}\) ions. Explain this observation.

Methanol can be prepared from carbon monoxide and hydrogen at high temperature and pressure in the presence of a suitable catalyst. (a) Write the expression for the equilibrium constant \(\left(K_{c}\right)\) for the reversible reaction \(2 \mathrm{H}_{2}(g)+\mathrm{CO}(g) \rightleftharpoons \mathrm{CH}_{3} \mathrm{OH}(g) \quad \Delta H=-90.2 \mathrm{kJ}\) (b) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\) and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if more \(\mathrm{H}_{2}\) is added? (c) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\) and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if CO is removed? (d) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\) and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if \(\mathrm{CH}_{3} \mathrm{OH}\) is added? (e) What will happen to the concentrations of \(\mathrm{H}_{2}, \mathrm{CO},\) and \(\mathrm{CH}_{3} \mathrm{OH}\) at equilibrium if the temperature of the system is increased?

How will an increase in temperature affect each of the following equilibria? How will a decrease in the volume of the reaction vessel affect each? (a) \(2 \mathrm{NH}_{3}(g) \rightleftharpoons \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \quad \Delta H=92 \mathrm{kJ}\) (b) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g) \quad \Delta H=181 \mathrm{kJ}\) (c) \(2 \mathrm{O}_{3}(g) \rightleftharpoons 3 \mathrm{O}_{2}(g) \quad \Delta H=-285 \mathrm{kJ}\) (d) \(\mathrm{CaO}(s)+\mathrm{CO}_{2}(g) \rightleftharpoons \mathrm{CaCO}_{3}(s) \quad \Delta H=-176 \mathrm{kJ}\)

Explain how to recognize the conditions under which changes in volume will affect gas-phase systems at equilibrium.

Show that the complete chemical equation, the total ionic equation, and the net ionic equation for the reaction represented by the equation \(\mathrm{KI}(a q)+\mathrm{I}_{2}(a q) \rightleftharpoons \mathrm{KI}_{3}(a q)\) give the same expression for the reaction quotient. \(\mathrm{KI}_{3}\) is composed of the ions \(K^{+}\) and \(I_{3}^{-}\)

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