Nitrosyl chloride, NOCl, decomposes to NO and Cl\(_2\). $$2 \mathrm{NOCl}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g)$$ Determine the rate law, the rate constant, and the overall order for this reaction from the following data: $$\begin{array}{|l|c|c|c|}\hline \text {\([\mathrm{NOCl}](M)\)}) & 0.10 & 0.20 & 0.30 \\\\\hline \text { Rate \(\left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{h}^{-1}\right)\)} & 8.0 \times 10^{-10} & 3.2 \times 10^{-9} & 7.2 \times 10^{-9} \\\\\hline\end{array}$$

Short Answer

Expert verified
The reaction is first-order with respect to NOCl, the rate law is rate = k [NOCl], and the rate constant k can be calculated from the given data.

Step by step solution

01

Determining the Reaction Order with Respect to NOCl

Examine how the rate changes as the concentration of NOCl is varied. Compare the rates and concentrations in pairs to determine the relationship between the rate and the concentration of NOCl.
02

Calculate the Reaction Order

Using the data from two experiments where the concentration of NOCl is changed, calculate the reaction order. For example, compare the first and second experiment, where the concentration of NOCl changes from 0.10 M to 0.20 M, and the rate changes from 8.0 x 10^-10 mol L^-1 h^-1 to 3.2 x 10^-9 mol L^-1 h^-1. Use the formula: rate = k [NOCl]^n to find the reaction order n, where k is the rate constant.
03

Determine the Rate Constant

Once the order with respect to NOCl is determined, use any of the given data points and the calculated order to solve for the rate constant k.
04

Write the Rate Law

Using the calculated reaction order and rate constant, write the rate law for the reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the study of the speed or rate at which chemical reactions occur and the factors that affect this rate. Understanding the pace at which reactants transform into products is crucial in various areas, including manufacturing, pharmaceuticals, and environmental science. The reaction rate is influenced by the concentration of reactants, the temperature of the system, the presence of a catalyst, and the physical state of the reactants.

Imagine we're observing the decomposition of nitrosyl chloride (NOCl) into nitric oxide (NO) and chlorine gas (Cl2). In kinetics, we track how rapidly this reaction proceeds under varying concentrations of NOCl. By looking at how the rate either quickens or slows down when we alter the reactant's concentration, we can deduce a mathematical relationship known as the rate law, which links the reaction rate to the concentration of each reactant.
Rate Constant
The rate constant, symbolized as 'k', is a proportionality factor in the rate law of a chemical reaction that relates the reaction rate to the concentrations of reactants. It is a unique value for every reaction at a specific temperature and is essential for calculating the speed of a reaction. The numerical value of the rate constant gives us insight into the reactivity of the elements involved; a larger 'k' implies a faster reaction.

In our examination of NOCl decomposition, once we've established the reaction order—essentially how the reaction rate is affected by the concentration of NOCl—we can use this information, along with the observed rates at known concentrations, to calculate the rate constant 'k'. This constant is crucial because it enables us to predict how fast the reaction will occur under different circumstances.
Reaction Order
Reaction order is the exponent to which the concentration of a reactant is raised in the rate law, indicating how the rate of reaction is affected by the reactant’s concentration. It can be zero, an integer, or even a fraction. The overall reaction order is the sum of the orders of all reactants included in the rate law equation.

For our specific reaction of NOCl breaking into NO and Cl2, the reaction order with respect to NOCl informs us how many molecules of NOCl are involved in the rate-determining step. To find this, we conduct experiments altering the concentration of NOCl and observing the change in the reaction rate. By comparing these rates, we use the method of initial rates to derive the exponent for NOCl concentration in the rate equation, giving us the reaction order regarding NOCl. This value not only tells us about how the concentration of NOCl impacts the rate but also helps in piecing together the mechanism of the reaction—how reactants proceed to form products at the molecular level.

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Most popular questions from this chapter

Regular flights of supersonic aircraft in the stratosphere are of concern because such aircraft produce nitric oxide, NO, as a byproduct in the exhaust of their engines. Nitric oxide reacts with ozone, and it has been suggested that this could contribute to depletion of the ozone layer. The reaction \(\mathrm{NO}+\mathrm{O}_{3} \longrightarrow \mathrm{NO}_{2}+\mathrm{O}_{2}\) is first order with respect to both \(\mathrm{NO}\) and \(\mathrm{O}_{3}\) with a rate constant of \(2.20 \times 10^{7} \mathrm{L} / \mathrm{mol} / \mathrm{s}\). What is the instantaneous rate of disappearance of NO when \([\mathrm{NO}]=3.3 \times 10^{-6} \mathrm{M}\) and \(\left[\mathrm{O}_{3}\right]=5.9 \times 10^{-7} \mathrm{M} ?\)

How does an increase in temperature affect rate of reaction? Explain this effect in terms of the collision theory of the reaction rate.

A study of the rate of the reaction represented as \(2 A \longrightarrow B\) gave the following data: $$\begin{array}{|c|c|c|c|c|c|c|c|} \hline \text { Time (s) } & 0.0 & 5.0 & 10.0 & 15.0 & 20.0 & 25.0 & 35.0 \\ \hline \text { \([A](M)\) } & 1.00 & 0.775 & 0.625 & 0.465 & 0.360 & 0.285 & 0.230 \\ \hline \end{array}$$ (a) Determine the average rate of disappearance of \(A\) between \(0.0 \mathrm{s}\) and \(10.0 \mathrm{s}\), and between \(10.0 \mathrm{s}\) and \(20.0 \mathrm{s}\). (b) Estimate the instantaneous rate of disappearance of \(A\) at 15.0 s from a graph of time versus \([A]\). What are the units of this rate? (c) Use the rates found in parts (a) and (b) to determine the average rate of formation of \(B\) between 0.00 s and 10.0 s, and the instantaneous rate of formation of \(B\) at 15.0 s.

Account for the increase in reaction rate brought about by a catalyst.

For the reaction \(Q \longrightarrow W+X,\) the following data were obtained at \(30^{\circ} \mathrm{C}:\) $$\begin{array}{|c|c|c|c|} \hline[Q]_{\text {initial }}(M) & 0.170 & 0.212 & 0.357 \\ \hline \text { Rate \(\left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{s}^{-1}\right)\) } & 6.68 \times 10^{-3} & 1.04 \times 10^{-2} & 2.94 \times 10^{-2} \\ \hline \end{array}$$ (a) What is the order of the reaction with respect to \([Q]\), and what is the rate law? (b) What is the rate constant?

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