Chapter 18: Problem 109
What is the oxidation state of the halogen in each of the following? (a) \(\mathrm{H}_{5} \mathrm{IO}_{6}\) (b) \(\mathrm{IO}_{4}^{-}\) (c) \(\mathrm{ClO}_{2}\) (d) ICl \(_{3}\) (e) \(\mathrm{F}_{2}\)
Short Answer
Expert verified
The oxidation states are as follows: (a) Iodine: +7 (b) Iodine: +7 (c) Chlorine: +4 (d) Iodine: +3 (e) Fluorine: 0.
Step by step solution
01
Understand the Concept of Oxidation States
Oxidation state (or oxidation number) represents the degree of oxidation of an atom in a chemical compound. It is a hypothetical charge that an atom would have if all bonds to atoms of different elements were completely ionic. Hydrogen typically has an oxidation state of +1, oxygen has an oxidation state of -2, and in a neutral molecule, the sum of oxidation states of all atoms must equal zero, while in a polyatomic ion, it should equal the ion’s charge.
02
Determine the Oxidation State for Halogen in \(\mathrm{H}_{5} \mathrm{IO}_{6}\)
Here, hydrogen has a +1 oxidation state and oxygen has a -2 oxidation state. There are 5 hydrogens and 6 oxygens, which contribute +5 and -12 to the overall charge, respectively. Since the compound is neutral, the oxidation state of iodine can be found using the equation: +5 + (oxidation state of I) - 12 = 0. Solving for the oxidation state of iodine (I) gives us +7.
03
Determine the Oxidation State for Halogen in \(\mathrm{IO}_{4}^{-}\)
This is a polyatomic ion with a charge of -1. Oxygen has a -2 oxidation state, contributing a total of -8 for four oxygen atoms. Using the equation: (oxidation state of I) - 8 = -1, solving for the oxidation state of iodine (I) gives us +7.
04
Determine the Oxidation State for Halogen in \(\mathrm{ClO}_{2}\)
In this molecule, oxygen again has an oxidation state of -2. With two oxygens, the total contribution from oxygen is -4. As the molecule is neutral, chlorine's oxidation state can be found by: (oxidation state of Cl) - 4 = 0. Solving for the oxidation state of chlorine (Cl) gives us +4.
05
Determine the Oxidation State for Halogen in ICl\(_{3}\)
This is a neutral molecule without oxygen. When halogens combine with each other, the more electronegative atom is assigned the negative oxidation state. Chlorine is more electronegative than iodine. Therefore, chlorine will have a -1 oxidation state (for each atom). Since there are three chlorines, iodine's oxidation state can be found by: (oxidation state of I) + 3(-1) = 0. Solving for the oxidation state of iodine (I) gives us +3.
06
Determine the Oxidation State for Halogen in \(\mathrm{F}_{2}\)
In elemental form, the oxidation state of any element is 0. Since \(\mathrm{F}_{2}\) is the elemental form of fluorine, its oxidation state is 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Redox Chemistry
Redox chemistry deals with the chemical processes involving oxidation and reduction reactions. These reactions are fundamental to understanding energy conversion, corrosion, signaling pathways, and many other chemical phenomena.
Oxidation is the process of losing electrons, leading to an increase in oxidation state, while reduction refers to the gain of electrons, resulting in a decrease in oxidation state. In any redox reaction, one species undergoes oxidation and another undergoes reduction, maintaining the principle of conservation of charge.
Oxidation is the process of losing electrons, leading to an increase in oxidation state, while reduction refers to the gain of electrons, resulting in a decrease in oxidation state. In any redox reaction, one species undergoes oxidation and another undergoes reduction, maintaining the principle of conservation of charge.
Importance of Oxidation States in Redox Reactions
Redox reactions often involve changes in oxidation states of the participating atoms. Tracking these changes helps chemists determine which species are oxidized and which are reduced. Understanding the oxidation state of the halogen in various compounds, as presented in the exercise, is crucial for interpreting or predicting the outcome of redox reactions.Oxidation Number Calculation
Calculating oxidation numbers is a fundamental skill in chemistry that aids in analyzing redox reactions. Oxidation numbers provide a way to keep track of electron flow during chemical reactions.
To calculate the oxidation number for an atom within a molecule or ion, several rules must be followed, such as knowing that the sum of the oxidation numbers must equal the net charge on the molecule or ion. For instance, hydrogen is typically assigned a +1 oxidation number except when bonded to metals in hydrides, and oxygen usually has an oxidation number of -2, except in peroxides or when bonded to fluorine.
To calculate the oxidation number for an atom within a molecule or ion, several rules must be followed, such as knowing that the sum of the oxidation numbers must equal the net charge on the molecule or ion. For instance, hydrogen is typically assigned a +1 oxidation number except when bonded to metals in hydrides, and oxygen usually has an oxidation number of -2, except in peroxides or when bonded to fluorine.
Steps for Calculation
To find the oxidation number of the halogen in the given exercises, you would assign known oxidation numbers to other atoms, such as hydrogen and oxygen, and then solve for the unknown oxidation number, ensuring that the overall charge balance is maintained. This method was applied to deduce the various oxidation states of iodine and chlorine in the provided compounds.Chemical Bonding
Chemical bonding is the force holding atoms together in compounds. Understanding the nature of chemical bonds is essential for explaining the properties and behaviors of substances.
There are several types of bonds, including ionic, covalent, and metallic bonds, each characterized by different electron distributions and exhibiting various properties. In oxidation number calculations, the type of bond can affect the assigned oxidation numbers. For example, in purely ionic bonding, electrons are assumed to be completely transferred from one atom to another. In reality, most bonds are not completely ionic, and oxidation numbers become useful for determining electron distribution in these cases.
There are several types of bonds, including ionic, covalent, and metallic bonds, each characterized by different electron distributions and exhibiting various properties. In oxidation number calculations, the type of bond can affect the assigned oxidation numbers. For example, in purely ionic bonding, electrons are assumed to be completely transferred from one atom to another. In reality, most bonds are not completely ionic, and oxidation numbers become useful for determining electron distribution in these cases.