Chapter 19: Problem 46
Would you expect the \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\) to be diamagnetic or paramagnetic? Explain your reasoning.
Short Answer
Expert verified
The compound \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\) is paramagnetic because the Cr\(^{3+}\) ions have unpaired electrons in their d-orbitals.
Step by step solution
01
Understand the concept of magnetism in compounds
To determine whether a compound is diamagnetic or paramagnetic, you need to know the electronic configuration of the atoms involved. Diamagnetic substances have all their electrons paired up, and therefore, do not have a net magnetic field. Paramagnetic substances have at least one unpaired electron, which creates a magnetic field that aligns with external magnetic fields.
02
Determine the electronic configuration of chromium
Chromium (Cr) has an atomic number of 24, which corresponds to the electron configuration [Ar]3d5 4s1. However, in the complex \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\), chromium is in a chemical environment that affects its electronic configuration. We must consider the charge of the complex to find the oxidation state of chromium.
03
Calculate the oxidation state of chromium in the complex
Cyanide (CN) is a -1 ligand and there are six of them, contributing -6 to the charge. Magnesium (Mg) has a +2 oxidation state naturally and there are three of them, contributing +6 overall. This means the complex is neutral, so the charge on each Cr must be +3 because there are two Cr which would contribute to +6 balancing the -6 from CN ligand. The electron configuration of Cr\(^{3+}\) would be [Ar]3d3, as three electrons are removed from the 4s and 3d orbitals.
04
Analyze the electron configuration for unpaired electrons
Cr\(^{3+}\) has three electrons in the 3d orbital. Since orbitals can hold a maximum of two electrons with opposite spins, we must have at least one unpaired electron in Cr\(^{3+}\).
05
Conclude the magnetic property of the compound
Since the chromium ions in the compound have unpaired electrons, the compound \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\) is paramagnetic.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnetic Properties of Compounds
Magnetic properties in compounds are fascinating as they are a direct result of the arrangement of electrons within an atom or molecule. These properties are primarily categorized into two types: diamagnetism and paramagnetism. Diamagnetic substances are those with all electrons paired up and show no permanent net magnetic moment. They are slightly repelled by a magnetic field. On the other hand, paramagnetic substances contain at least one unpaired electron and are attracted into a magnetic field due to the magnetic moments arising from these unpaired electrons.
When a paramagnetic compound is placed in a magnetic field, the unpaired electrons' spins align with the field, creating a magnetization in the direction of the field. This attraction is relatively weak and disappears once the external field is removed. In the diamagnetic case, an induced magnetic field opposes the applied field, but this too vanishes when the external influence is gone. Understanding the source of these magnetic behaviors involves delving into the electronic configurations of the atoms or ions in question.
For a student trying to determine the magnetic nature of a compound, it's essential to map out the electrons and spot the existence, or lack, of unpaired electrons. It's a step-by-step approach that begins with breaking down the compound's formula to examine the constituent ions or atoms and ends with applying principles of electron configuration.
When a paramagnetic compound is placed in a magnetic field, the unpaired electrons' spins align with the field, creating a magnetization in the direction of the field. This attraction is relatively weak and disappears once the external field is removed. In the diamagnetic case, an induced magnetic field opposes the applied field, but this too vanishes when the external influence is gone. Understanding the source of these magnetic behaviors involves delving into the electronic configurations of the atoms or ions in question.
For a student trying to determine the magnetic nature of a compound, it's essential to map out the electrons and spot the existence, or lack, of unpaired electrons. It's a step-by-step approach that begins with breaking down the compound's formula to examine the constituent ions or atoms and ends with applying principles of electron configuration.
Electronic Configuration
Electronic configuration serves as the bedrock for understanding the behavior of atoms and molecules in various chemical settings, including their magnetic properties. It refers to the distribution of electrons in an atom's or ion's orbitals, following a set of rules known as Aufbau principle, Pauli exclusion principle, and Hund's rule.
The Aufbau principle states that electrons fill orbitals starting from the lowest energy level, moving to higher levels progressively. The Pauli exclusion principle restricts an orbital to holding a maximum of two electrons with opposite spins. Hund's rule explains that, for orbitals of the same energy, electrons fill them singly first, with parallel spins, before doubling up.
As seen in the example of chromium in the compound \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\), the atomic number dictates the neutral atom's electron configuration. But when we delve into compounds and ions, their configurations can shift. For instance, chromium ions in the exercise lose electrons, leading to a change in their configuration, which in turn alters their magnetic properties. This sort of consideration is pivotal not only in explaining magnetism but also in predicting reactivity, color, and other chemical phenomena.
The Aufbau principle states that electrons fill orbitals starting from the lowest energy level, moving to higher levels progressively. The Pauli exclusion principle restricts an orbital to holding a maximum of two electrons with opposite spins. Hund's rule explains that, for orbitals of the same energy, electrons fill them singly first, with parallel spins, before doubling up.
As seen in the example of chromium in the compound \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\), the atomic number dictates the neutral atom's electron configuration. But when we delve into compounds and ions, their configurations can shift. For instance, chromium ions in the exercise lose electrons, leading to a change in their configuration, which in turn alters their magnetic properties. This sort of consideration is pivotal not only in explaining magnetism but also in predicting reactivity, color, and other chemical phenomena.
Oxidation State Calculation
Oxidation state is a vital concept that gives insight into the electronic configuration and bonding scenario of an element in a compound. It's a hypothetical charge an atom would have if all bonds it formed were completely ionic. Calculating the oxidation state involves a certain amount of arithmetic alongside a good understanding of the typical charges of common ions and the rules governing oxidation numbers.
In general, the sum of oxidation states in a neutral compound must be zero. When dealing with ions, the sum should equal the ion's charge. Taking the exercise's compound, \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\), involves accounting for known oxidation states, like +2 for Mg and -1 for each CN- ligand. The calculation then deduces the necessary oxidation state of chromium to achieve charge neutrality in the compound. It's through this process that students can work out the electron configuration for the chromium ion and thus predict the magnetic character of the compound.
By learning to calculate oxidation states, students equip themselves to predict a variety of chemical properties and behaviors, building a bridge between abstract numbers and tangible chemical characteristics.
In general, the sum of oxidation states in a neutral compound must be zero. When dealing with ions, the sum should equal the ion's charge. Taking the exercise's compound, \(\mathrm{Mg}_{3}\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]_{2}\), involves accounting for known oxidation states, like +2 for Mg and -1 for each CN- ligand. The calculation then deduces the necessary oxidation state of chromium to achieve charge neutrality in the compound. It's through this process that students can work out the electron configuration for the chromium ion and thus predict the magnetic character of the compound.
By learning to calculate oxidation states, students equip themselves to predict a variety of chemical properties and behaviors, building a bridge between abstract numbers and tangible chemical characteristics.