Chapter 2: Problem 59
. A certain nut crunch cereal contains 11.0 grams of sugar (sucrose, \(C_{12} \mathrm{H}_{22} \mathrm{O}_{11}\) ) per serving size of 60.0 grams. How many servings of this cereal must be eaten to consume 0.0278 moles of sugar?
Short Answer
Expert verified
To consume 0.0278 moles of sugar, divide 0.0278 moles by the moles of sucrose per 60.0-gram serving of the cereal to get the number of servings needed.
Step by step solution
01
Calculate the molar mass of sucrose
First, find the molar mass of sucrose (C_{12}H_{22}O_{11}) by adding the atomic masses of its constituent atoms. Sucrose is composed of 12 carbon (C) atoms, 22 hydrogen (H) atoms, and 11 oxygen (O) atoms. Carbon has an atomic mass of approximately 12.01 g/mol, hydrogen 1.01 g/mol, and oxygen 16.00 g/mol. Hence, the molar mass of sucrose is (12 * 12.01) + (22 * 1.01) + (11 * 16.00) grams per mole.
02
Calculate the number of moles in one serving
Now that you have the molar mass of sucrose, use it to find the number of moles in one serving of cereal. There are 11.0 grams of sucrose per serving. Divide this by the molar mass of sucrose to find the moles in one serving: moles per serving = grams per serving / molar mass of sucrose.
03
Determine the number of servings for 0.0278 moles
To find out how many servings are needed to consume 0.0278 moles of sugar, divide the total desired moles (0.0278 moles) by the moles of sugar per serving calculated in Step 2: number of servings = total moles of sugar / moles of sugar per serving.
04
Calculate and interpret the result
Finally, perform the division from Step 3 to obtain the number of servings required. If the result is a decimal, you must round up to the nearest whole serving since you cannot have a fraction of a serving. The result gives us the number of servings of the cereal one must eat to consume 0.0278 moles of sugar.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass Calculation
Understanding molar mass is fundamental to solving a wide array of chemistry problems, including stoichiometry ones like the one in our exercise. The molar mass represents the mass of one mole of a substance, expressed in grams per mole (g/mol). A mole is a standard unit that measures the quantity of a substance in terms of the amount of particles it contains, speaking very simply, one mole is roughly equal to Avogadro's number, which is approximately 6.022 x 1023 particles.
To calculate the molar mass of sucrose, or any substance, we sum the atomic masses of all the atoms in one molecule of the substance. These atomic masses can typically be found on the periodic table and are measured in atomic mass units (amu). However, conveniently, the atomic mass in amu is numerically identical to the molar mass in g/mol for that element. For sucrose, which has the chemical formula \(C_{12}H_{22}O_{11}\), add the molar masses of 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
To calculate the molar mass of sucrose, or any substance, we sum the atomic masses of all the atoms in one molecule of the substance. These atomic masses can typically be found on the periodic table and are measured in atomic mass units (amu). However, conveniently, the atomic mass in amu is numerically identical to the molar mass in g/mol for that element. For sucrose, which has the chemical formula \(C_{12}H_{22}O_{11}\), add the molar masses of 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
Calculating Sucrose's Molar Mass:
The molar mass of carbon is about 12.01 g/mol, hydrogen is about 1.01 g/mol, and oxygen is about 16.00 g/mol. Therefore, for sucrose:- Carbon: \(12 \times 12.01\ g/mol = 144.12\ g/mol\)
- Hydrogen: \(22 \times 1.01\ g/mol = 22.22\ g/mol\)
- Oxygen: \(11 \times 16.00\ g/mol = 176.00\ g/mol\)
Moles to Grams Conversion
Stoichiometry problems frequently require conversion between moles and grams. As we've noted, the molar mass connects these two units: it tells us the mass of one mole of a substance. To convert moles to grams, we multiply the number of moles by the molar mass of the substance. Conversely, to convert grams to moles, we divide the mass of the substance by its molar mass.
Let's apply this to our cereal problem. Once we've calculated the molar mass of sucrose, we can tackle the conversion:
Let's apply this to our cereal problem. Once we've calculated the molar mass of sucrose, we can tackle the conversion:
- To find moles from grams (given in the problem as 11.0 grams of sucrose per serving), you'd divide by the molar mass of sucrose.
- To determine grams from moles (the overall goal, 0.0278 moles of sugar), you'd multiply by the molar mass of sucrose.
Chemical Formula of Sucrose
The chemical formula of a compound is a representation of the elements that make up that compound and the proportion of each element. For sucrose, its chemical formula is \(C_{12}H_{22}O_{11}\). Understanding this formula is vital, as it directly informs the molar mass calculation.
This formula indicates that each molecule of sucrose consists of 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms. Recognizing the chemical formula also assists with visualizing the structure of the molecule and predicting how it will interact with other substances in chemical reactions. In the context of the cereal problem, the chemical formula helps us to understand what sugar (in this case, sucrose) is at a molecular level and why its molar mass is calculated as it is. Knowing the formula enables us not just to calculate molar mass, but also to infer properties and behaviors of the molecule in various chemical scenarios, such as energy content, solubility, and reaction outcomes.
This formula indicates that each molecule of sucrose consists of 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms. Recognizing the chemical formula also assists with visualizing the structure of the molecule and predicting how it will interact with other substances in chemical reactions. In the context of the cereal problem, the chemical formula helps us to understand what sugar (in this case, sucrose) is at a molecular level and why its molar mass is calculated as it is. Knowing the formula enables us not just to calculate molar mass, but also to infer properties and behaviors of the molecule in various chemical scenarios, such as energy content, solubility, and reaction outcomes.