Chapter 21: Problem 56
Write the two resonance structures for the pyridinium ion, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}\)
Short Answer
Expert verified
The two resonance structures have alternate placement of the double bonds within the ring while maintaining the positive charge on the nitrogen atom.
Step by step solution
01
Identify the structure of pyridinium ion
The pyridinium ion is a six-membered aromatic ring with five carbon atoms and one nitrogen atom. The nitrogen atom is sp2 hybridized and carries a positive charge by owning one lone pair less than it would in a neutral state.
02
Draw the first resonance structure
Draw the hexagonal ring of the pyridinium ion with alternate single and double bonds, with the nitrogen atom bonded to a hydrogen atom. Indicate the positive charge on the nitrogen atom.
03
Locate the double bonds
Note that the double bonds are between carbon 2 and carbon 3, carbon 4 and carbon 5 in the first resonance structure.
04
Draw the second resonance structure
Shift one of the double bonds to the position adjacent to the original double bond and draw the new structure. The new double bond should be between carbon 3 and carbon 4, and between carbon 5 and the nitrogen atom.
05
Double check for aromaticity
Ensure that the new resonance structure maintains aromatic character; the ring must maintain conjugation and follow Huckel's rule of 4n+2 pi electrons (n is an integer).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Resonance in Chemistry
Resonance in chemistry refers to the phenomenon where a single molecule is best described by two or more structures, known as resonance structures or contributing forms. These structures are not actual separate entities but are hypothetical constructs that represent different electron distributions. The real molecule is a hybrid of these contributing forms, with the characteristics of all included in its actual structure.
For resonance to be applicable, the molecule must have a conjugated system where alternating single and double bonds allow electrons to delocalize across the structure. The electrons are not static but can move through the p-orbitals of adjacent atoms, which leads to a stabilization of the molecule. This is essential in understanding the stability of many organic compounds, including aromatic systems like the pyridinium ion in the exercise above.
It's important to note that resonance structures must have the same number of electrons, the same molecular formula, and must only differ in the distribution of electrons and not the arrangement of atoms. Each resonance structure contributes to the resonance hybrid, which reflects the true nature of the molecule. The most stable and representative structure contributes the most.
For resonance to be applicable, the molecule must have a conjugated system where alternating single and double bonds allow electrons to delocalize across the structure. The electrons are not static but can move through the p-orbitals of adjacent atoms, which leads to a stabilization of the molecule. This is essential in understanding the stability of many organic compounds, including aromatic systems like the pyridinium ion in the exercise above.
It's important to note that resonance structures must have the same number of electrons, the same molecular formula, and must only differ in the distribution of electrons and not the arrangement of atoms. Each resonance structure contributes to the resonance hybrid, which reflects the true nature of the molecule. The most stable and representative structure contributes the most.
Aromatic Compounds
Aromatic compounds are a class of molecules recognized by their unique stability and electronic configuration. The quintessential example of an aromatic compound is benzene, which comprises a ring of six carbon atoms, with alternating single and double bonds allowing for resonance.
Aromaticity imparts special chemical properties, including lower reactivity in certain types of chemical reactions compared to non-aromatic compounds. This is due to the delocalization of electrons within the ring; in benzene's case, the six pi electrons are shared across the ring structure, leading to exceptional stability known as aromatic stabilization.
In the exercise, the pyridinium ion represents an aromatic compound with a heterocyclic ring, which means it includes an atom other than carbon — in this case, nitrogen. The presence of this heteroatom affects the compound's electronic properties and has implications on its chemistry. The positive charge on the nitrogen atom in such heteroaromatic compounds can contribute to the resonance through its ability to participate in the delocalized electron system.
Aromaticity imparts special chemical properties, including lower reactivity in certain types of chemical reactions compared to non-aromatic compounds. This is due to the delocalization of electrons within the ring; in benzene's case, the six pi electrons are shared across the ring structure, leading to exceptional stability known as aromatic stabilization.
In the exercise, the pyridinium ion represents an aromatic compound with a heterocyclic ring, which means it includes an atom other than carbon — in this case, nitrogen. The presence of this heteroatom affects the compound's electronic properties and has implications on its chemistry. The positive charge on the nitrogen atom in such heteroaromatic compounds can contribute to the resonance through its ability to participate in the delocalized electron system.
Huckel's Rule
Huckel's rule is pivotal in determining whether a planar ring molecule can be considered aromatic or not. It states that for a molecule to exhibit aromaticity, it must have a closed loop of overlapping p-orbitals and a total of 4n+2 pi electrons, where n is a non-negative integer (n = 0, 1, 2, 3, ...).
Applying Huckel's rule helps chemists understand why some structures are exceptionally stable. For the pyridinium ion provided in the exercise, the presence of 6 electrons in the conjugated pi system (5 from the carbon atoms and 1 from the nitrogen atom) follows the 4n+2 rule where n = 1, since 4(1) + 2 = 6. The ion is therefore aromatic, contributing to its structural stability.
This rule is an essential tool for predicting aromaticity in molecules, which further provides insights into their reactivity and properties. When drawing resonance structures for aromatic compounds, it is crucial to maintain the continuous pi system and ensure that the 4n+2 rule is satisfied in each contributing form for the compound to retain its aromatic character and stability.
Applying Huckel's rule helps chemists understand why some structures are exceptionally stable. For the pyridinium ion provided in the exercise, the presence of 6 electrons in the conjugated pi system (5 from the carbon atoms and 1 from the nitrogen atom) follows the 4n+2 rule where n = 1, since 4(1) + 2 = 6. The ion is therefore aromatic, contributing to its structural stability.
This rule is an essential tool for predicting aromaticity in molecules, which further provides insights into their reactivity and properties. When drawing resonance structures for aromatic compounds, it is crucial to maintain the continuous pi system and ensure that the 4n+2 rule is satisfied in each contributing form for the compound to retain its aromatic character and stability.