Answer the following questions about a Blu-ray laser:
(a) The laser on a Blu-ray player has a wavelength of \(405 \mathrm{nm}\). In
what region of the electromagnetic spectrum is this radiation? What is its
frequency?
(b) A Blu-ray laser has a power of 5 milliwatts ( 1 watt \(=1\ \mathrm{J}\
\mathrm{s}^{-1}\) ). How many photons of light are produced by the laser in 1
hour?
(c) The ideal resolution of a player using a laser (such as a Blu-ray player),
which determines how close together data can be stored on a compact disk, is
determined using the following formula: Resolution \(=0.60(\lambda \text { NA),
where } \lambda\) is the wavelength of the laser and NA is the numerical
aperture. Numerical aperture is a measure of the size of the spot of light on
the disk; the larger the NA, the smaller the spot. In a typical Blu-ray
system, NA = 0.95. If the 405-nm laser is used in a Blu-ray player, what is
the closest that information can be stored on a Blu-ray disk?
(d) The data density of a Blu-ray disk using a 405 -nm laser is \(1.5 \times
10^{7}\) bits \(\mathrm{mm}^{-2}\). Disks have an outside diameter of \(120
\mathrm{mm}\) and a hole of \(15-\mathrm{mm}\) diameter. How many data bits can
be contained on the disk? If a Blu-ray disk can hold 9,400,000 pages of text,
how many data bits are needed for a typed page? (Hint: Determine the area of
the disk that is available to hold data. The area inside a circle is given by
\(\mathrm{A}=\pi r^{2},\) where the radius \(r\) is one-half of the diameter.)