Determine the empirical formulas for compounds with the following percent compositions: (a) 43.6\% phosphorus and 56.4\% oxygen (b) 28.7\% K, 1.5\% H, 22.8\% P, and 47.0\% O

Short Answer

Expert verified
Compound (a) empirical formula: P2O5. Compound (b) empirical formula: K3PO4.

Step by step solution

01

- Convert Percentage to Mass - Compound (a)

Assume a 100 g sample of the compound. This means we have 43.6 g of phosphorus (P) and 56.4 g of oxygen (O).
02

- Calculate Moles of Each Element - Compound (a)

Divide the mass of each element by its atomic mass to find the moles. For P, use 30.97 g/mol, and for O, use 16.00 g/mol.
03

- Determine the Mole Ratio - Compound (a)

Divide the number of moles of each element by the smallest number of moles calculated to get the simplest whole number ratio.
04

- Derive the Empirical Formula - Compound (a)

Use the mole ratio to write the empirical formula by giving the elements their respective subscripts in the formula.
05

- Convert Percentage to Mass - Compound (b)

Assume a 100 g sample. This gives us 28.7 g of potassium (K), 1.5 g of hydrogen (H), 22.8 g of phosphorus (P), and 47.0 g of oxygen (O).
06

- Calculate Moles of Each Element - Compound (b)

Calculate the moles for each element using their atomic masses (K = 39.10 g/mol, H = 1.008 g/mol, P = 30.97 g/mol, and O = 16.00 g/mol).
07

- Determine the Mole Ratio - Compound (b)

Divide the number of moles of each element by the smallest number of moles from the results to get a whole number ratio.
08

- Derive the Empirical Formula - Compound (b)

If necessary, multiply the mole ratios by a common factor to get whole numbers and write the empirical formula for compound (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percent Composition
The percent composition of an element in a compound represents the percentage of the total mass of the compound that is attributable to that element. It's a fundamental concept in chemistry that helps us understand the makeup of compounds. To visualize this, imagine a cake made up of different ingredients. Each ingredient represents a component of the compound, and the percent composition tells you how much of each ingredient is in the cake.

For instance, if we're given the percent composition of a compound like in the exercise example, we can think of a 100 g total mass to make the math straightforward. If a compound is 43.6% phosphorus, it's like saying that out of a 100 g cake, 43.6 g is phosphorus. This analogy simplifies the understanding of percent composition and sets the stage for further calculations like converting these percentages into mass, which is crucial for determining the empirical formula of the compound.
Mole Ratio
A mole ratio is a comparison of the amount of moles of one substance to the amount of moles of another substance in a chemical reaction. It's derived from the balanced chemical equation and is essential for calculations in stoichiometry. Think of moles like counting items in a bag: if you have one bag of apples and one bag of oranges, the mole ratio tells you how many apples there are compared to oranges.

In our textbook example for determining empirical formulas, the mole ratio translates to finding the simplest whole number ratio of elements after converting the masses of those elements to moles. By dividing the moles of each element by the smallest number of moles present, we obtain this ratio. The empirical formula is expressed in terms of this mole ratio, symbolizing the simplest whole-number combination of the elements.
Molecular Formula
The molecular formula is a notation that depicts the actual number of atoms of each element in one molecule of a compound. It's related to but not the same as the empirical formula, which shows the simplest integer ratio of elements in a compound. The molecular formula can be a multiple of the empirical formula.

For example, the empirical formula of glucose is CH2O, indicating the simplest ratio of carbon, hydrogen, and oxygen atoms. However, the molecular formula is C6H12O6, which tells us there are actually six times more of each atom in each molecule of glucose. To determine the molecular formula, you need the compound's empirical formula and its molar mass; then, by comparing the molar mass of the empirical formula to the molar mass of the compound, you can find the factor by which to multiply the empirical formula.
Chemical Composition Analysis
Chemical composition analysis involves determining the percentage of different elements within a chemical compound. It's an essential process in chemistry that can be utilized to verify and understand the exact makeup of a substance. This analysis is crucial in fields like materials science, pharmacology, and quality control.

In the context of our exercise, chemical composition analysis is the starting point for finding the empirical formula. It's initiated by converting the percent composition to mass, as if we were analyzing a 100-gram sample of the compound. This straightforward approach allows us to determine the moles of each element. These moles are then used to find the mole ratio and, ultimately, the empirical formula, which provides us with the simplest representation of the compound's composition in terms of its constituent elements.

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