Citric acid, \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7},\) a component of jams, jellies, and fruity soft drinks, is prepared industrially via fermentation of sucrose by the mold Aspergillus niger. The equation representing this reaction is \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+\mathrm{H}_{2} \mathrm{O}+3 \mathrm{O}_{2} \longrightarrow 2 \mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}+4 \mathrm{H}_{2} \mathrm{O}\) What mass of citric acid is produced from exactly 1 metric ton \(\left(1.000 \times 10^{3} \mathrm{kg}\right)\) of sucrose if the yield is \(92.30 \%\) ?

Short Answer

Expert verified
926.4 kg of citric acid is produced.

Step by step solution

01

Write the balanced chemical equation

The reaction for the production of citric acid is given as: \(\mathrm{C}_{12}\mathrm{H}_{22}\mathrm{O}_{11} + \mathrm{H}_{2}\mathrm{O} + 3\mathrm{O}_{2} \rightarrow 2\mathrm{C}_{6}\mathrm{H}_{8}\mathrm{O}_{7} + 4\mathrm{H}_{2}\mathrm{O}\).
02

Calculate molar masses

Calculate the molar mass of sucrose \(\mathrm{C}_{12}\mathrm{H}_{22}\mathrm{O}_{11}\) and citric acid \(\mathrm{C}_{6}\mathrm{H}_{8}\mathrm{O}_{7}\). Molar mass of sucrose is \(12\times12 + 22\times1 + 11\times16 = 342\ g/mol\). Molar mass of citric acid is \(6\times12 + 8\times1 + 7\times16 = 192\ g/mol\).
03

Convert mass of sucrose to moles

Convert 1 metric ton of sucrose to grams and then to moles. \(1.000 \times 10^3 \mathrm{kg} = 1.000 \times 10^6 \mathrm{g}\). Moles of sucrose is \(\frac{1.000 \times 10^6 \mathrm{g}}{342 \mathrm{g/mol}}\).
04

Use stoichiometry to find moles of citric acid

Based on the balanced equation, 1 mole of sucrose produces 2 moles of citric acid. Calculate the moles of citric acid produced using the moles of sucrose.
05

Convert moles of citric acid to grams

Use the molar mass of citric acid to convert the moles to grams.
06

Apply the percent yield

Calculate the actual yield by taking \(92.30\%\) of the theoretical yield of citric acid.
07

Convert grams of citric acid to kilograms

Since the answer is requested in metric tons, convert the final mass from grams to kilograms. Remember that 1 kilogram is equal to 1000 grams.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is like a mathematical recipe for chemistry. It tells us how much of each substance is involved in a chemical reaction. By knowing the proportions of reactants and products, we can predict the output of a reaction under certain conditions. For instance, in the case of citric acid production, the stoichiometry of the reaction helps us understand that one mole of sucrose yields two moles of citric acid. Why is this important? Because it sets the stage for all the subsequent steps. Without the stoichiometric ratio, we wouldn't be able to move on to calculating how much product is actually produced from a given amount of reactant.

Let's illustrate this further with our citric acid reaction. If you were to imagine sucrose molecules entering a chemical 'dance', stoichiometry tells us that for every 'dance partner', it can create two citric acid molecules. This 1:2 ratio is crucial when we go ahead to calculate how much citric acid we get from a big 'dance party' of one metric ton of sucrose.
Molar Mass Calculation
Think of molar mass as the 'weight' of a chemical compound in a mole. One mole of any substance contains Avogadro's number of entities, which is approximately 6.022 x 10^23. By adding up the weights of each individual element from the periodic table, we can calculate how much one mole of that substance weighs in grams. In our example, we calculated the molar mass of sucrose to be 342 g/mol, which is like saying one mole of sugar weighs 342 grams. Similarly, for citric acid, with a molar mass of 192 g/mol, one mole of citric acid would weigh 192 grams.

Why is molar mass essential? Because it bridges the gap between the microscopic world of atoms and molecules and the macroscopic world we live in. By knowing the molar mass, we can convert grams to moles (a concept fundamental in stoichiometry) and vice versa, moving one step closer to the real quantities we handle in the laboratory or industry.
Chemical Reaction Yield
In a perfect world, every chemical reaction would go to completion, and all of the reactants would become products. However, in the real world, various factors prevent this from happening. Chemical reaction yield tells us how effectively a chemical reaction converts reactants into products. There are two types of yields: the theoretical yield, which is the maximum amount of product that could be formed from the given amounts of reactants, and the actual yield, which is the amount of product actually produced in the reaction.

In our citric acid production example, a yield of 92.30% doesn't mean the reaction was inefficient; it reflects the reality of the chemical process. This actual yield is what one would practically obtain in the lab or in large-scale production, taking into account that some sucrose might not react or some citric acid might be lost in the process. Calculating the reaction yield is thus a critical step in translating stoichiometric predictions into practical outputs.
Balanced Chemical Equation
A balanced chemical equation is the starting point of any stoichiometric calculation. It is a representation of a chemical reaction where the number of atoms of each element is the same on both sides of the equation. This balance is due to the Law of Conservation of Mass, which states that mass cannot be created or destroyed in a chemical reaction. In the context of citric acid production, the balanced equation provided in the problem ensures that the sucrose is transformed into citric acid in a way that conserves the atoms involved.

To deepen the understanding, consider the balanced equation as a precise instruction manual. It tells us the exact proportions, or 'recipe', needed to produce citric acid from sucrose. By adhering to this manual, chemists can calculate how much of each ingredient is needed and predict the amount of citric acid that will be made. If the equation were unbalanced, our calculations could lead to incorrect quantities, affecting the efficiency and economics of the production process.

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Most popular questions from this chapter

Write a balanced equation describing each of the following chemical reactions. (a) Solid potassium chlorate, \(\mathrm{KClO}_{3}\), decomposes to form solid potassium chloride and diatomic oxygen gas. (b) Solid aluminum metal reacts with solid diatomic iodine to form solid \(\mathrm{Al}_{2} \mathrm{I}_{6}\) (c) When solid sodium chloride is added to aqueous sulfuric acid, hydrogen chloride gas and aqueous sodium sulfate are produced. (d) Aqueous solutions of phosphoric acid and potassium hydroxide react to produce aqueous potassium dihydrogen phosphate and liquid water.

Consider molecular, complete ionic, and net ionic equations. (a) What is the difference between these types of equations? (b) In what circumstance would the complete and net ionic equations for a reaction be identical?

From the balanced molecular equations, write the complete ionic and net ionic equations for the following: (a) \(\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \rightarrow 2 \mathrm{KOH}(a q)+\mathrm{BaC}_{2} \mathrm{O}_{4}(s)\) (b) \(\operatorname{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{PbSO}_{4}(s)+2 \mathrm{HNO}_{3}(a q)\) (c) \(\mathrm{CaCO}_{3}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{CaSO}_{4}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)\)

Outline the steps needed to determine the limiting reactant when \(30.0 \mathrm{g}\) of propane, \(\mathrm{C}_{3} \mathrm{H}_{8}\), is bumed with \(75.0 \mathrm{g}\) of oxygen. Determine the limiting reactant.

Determine the oxidation states of the elements in the following compounds: (a) NaI (b) \(\mathrm{GdCl}_{3}\) (c) \(\operatorname{LiNO}_{3}\) (d) \(\mathrm{H}_{2} \mathrm{Se}\) (e) \(\mathrm{Mg}_{2} \mathrm{Si}\) (f) \(\mathrm{RbO}_{2}\), rubidium superoxide (g) HF

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