Chapter 9: Problem 27
The addition of 3.15 g of \(\mathrm{Ba}(\mathrm{OH})_{2} \cdot 8 \mathrm{H}_{2} \mathrm{O}\) to a solution of \(1.52 \mathrm{g}\) of \(\mathrm{NH}_{4} \mathrm{SCN}\) in \(100 \mathrm{g}\) of water in a calorimeter caused the temperature to fall by \(3.1^{\circ} \mathrm{C} .\) Assuming the specific heat of the solution and products is \(4.20 \mathrm{J} / \mathrm{g}^{\circ} \mathrm{C}\) calculate the approximate amount of heat absorbed by the reaction, which can be represented by the following equation: $$\mathrm{Ba}(\mathrm{OH})_{2} \cdot 8 \mathrm{H}_{2} \mathrm{O}(s)+2 \mathrm{NH}_{4} \mathrm{SCN}(a q) \longrightarrow \mathrm{Ba}(\mathrm{SCN})_{2}(a q)+2 \mathrm{NH}_{3}(a q)+10 \mathrm{H}_{2} \mathrm{O}(I)$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.