Determine the mass of iron (in kilograms) contained in \(22.8\) kilograms of \(\mathrm{Fe}_{2} \mathrm{O}_{3} .\)

Short Answer

Expert verified
The mass of iron contained in \(22.8\) kilograms of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is approximately \(15.94768\) kilograms.

Step by step solution

01

Determine the molar mass of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\)

To find the molar mass of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\), add the molar masses of 2 iron (Fe) atoms and 3 oxygen (O) atoms. The molar mass of Fe is approximately \(55.845\) grams per mole, and the molar mass of O is approximately \(16.00\) grams per mole. Therefore, the molar mass of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is \(2 \cdot 55.845 + 3 \cdot 16.00 = 111.69 + 48.00 = 159.69\) grams per mole.
02

Calculate the moles of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in \(22.8\) kilograms

Convert \(22.8\) kilograms to grams by multiplying by \(1000\), since there are \(1000\) grams in a kilogram. This gives us \(22,800\) grams. To find the number of moles, divide the mass by the molar mass: \(\frac{22,800 \text{ grams}}{159.69 \text{ grams/mole}} \approx 142.8 \text{ moles of } \mathrm{Fe}_{2} \mathrm{O}_{3}\).
03

Calculate the moles of iron (Fe) contained in the compound

Every mole of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) contains 2 moles of iron. Therefore, \(142.8 \text{ moles of } \mathrm{Fe}_{2} \mathrm{O}_{3}\) will contain \(2 \cdot 142.8 = 285.6 \text{ moles of Fe}\).
04

Calculate the mass of iron (Fe)

Multiply the number of moles of iron by the molar mass of iron to find the mass in grams: \(285.6 \text{ moles of Fe} \cdot 55.845 \text{ grams/mole} = 15,947.68 \text{ grams of Fe}\). To find the mass in kilograms, divide by \(1000\): \(\frac{15,947.68 \text{ grams}}{1000} = 15.94768 \text{ kilograms}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Stoichiometry
Stoichiometry is the area of chemistry that pertains to the quantitative relationships between the reactants and products in a chemical reaction. Imagine it as a recipe; to bake a cake, you need a certain amount of ingredients. Similarly, to form a specific chemical product, you need precise quantities of reactants.

Using stoichiometry, scientists can predict how much product will be formed from given amounts of reactants or vice versa. When calculating stoichiometry in a chemical reaction, we look at the balanced chemical equation and use the mole ratios of the reactants and products. A balanced equation serves as a conversion factor that allows us to convert between the amount of reactants used and the amount of products formed.

In the example provided, you first calculated the molar mass of iron(III) oxide and then used the mass given to find the amount in moles, adhering to the stoichiometric ratios detailed in the formula. This is an essential skill in chemistry as it allows us to understand the flow of matter during a reaction and is helpful in many practical applications such as medicine dosage, industrial chemical synthesis, and environmental studies.
Deciphering the Chemical Formula
A chemical formula represents the types and numbers of atoms in a molecule. For instance, the chemical formula \(\mathrm{Fe}_2\mathrm{O}_3\) tells us that each molecule is composed of two iron (Fe) atoms and three oxygen (O) atoms. In this formula, the subscript numbers indicate the quantity of each type of atom within the compound.

In terms of molecular composition, the chemical formula offers a blueprint that indicates the ratio of atoms. This information is critical for understanding the stoichiometry of a reaction because it defines the mole ratio of the different elements within a substance. When it comes to analyzing a substance like iron(III) oxide, the chemical formula also provides us with information required to compute its molar mass by adding together the molar masses of the respective elements as shown in the exercise evaluated.

A sound grasp of interpreting chemical formulas is crucial for budding chemists as it is the foundation for predicting the outcomes of chemical reactions, understanding material properties, and evaluating the purity of substances.
The Mole Concept in Chemistry
The mole concept is a bridge between the atomic scale and the real-world scale. One mole is defined as the amount of substance that contains as many particles (atoms, molecules, ions, or electrons) as there are atoms in 12 grams of carbon-12. This number, known as Avogadro's number, is approximately \(6.022 \times 10^{23}\) entities per mole.

With the mole concept, you can connect the microscopic world of atoms to the macroscopic world of grams and liters that we can measure. When chemists talk about the molar mass, which is the mass per mole of a substance, they are essentially indicating how heavy one mole of a particular substance is.

In our exercise, we use the mole concept to convert the mass of iron(III) oxide to moles. This conversion is fundamental as it allows us to then calculate how many moles of iron alone are present, which ultimately leads to the determination of the mass of iron in the sample following the stoichiometry of the compound. In the real world, the mole concept is pivotal for experiments, quantifying chemical reactions, and even in industries for manufacturing products with precision.

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