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Chapter 18: Q159CP (page 828)

Human urine has a normal pH of 6.2. If a person eliminates an average of 1250mL of urine per day, how manyH+ions are eliminated per week?

Short Answer

Expert verified

3.3×1018H+ions are eliminated

Step by step solution

01

To find how many H +  ions are eliminated

First solve for theH3O+ from the given pH

role="math" localid="1663313092236" pH =- logH3O+H3O+=10- pH= 10- 6.2=6.31×10-7M

Solve for the number of ions by converting it to moles and using Avogadro's number.

no. ofH+ions =6.32×10-7M×1.250L×6.022×1023H+ions1molHno. ofH+ions =4.75×1017H+ions

4.75×1017H+ions are eliminated per day. Multiply that by 7 days a week 3.3×1018H+.ions are eliminated from an average person's body per week.

Hence, 3.3×1018H+are eliminated.

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