Write theexpression for each of the following in water:

(a)${\mathbf{\text{CH}}}_{\mathbf{\text{3}}}{\mathbf{\text{NH}}}_{\mathbf{\text{3}}}^{\mathbf{\text{+}}}$

(b)role="math" localid="1657022192179" $\mathbf{\text{HClO}}$

(c)role="math" localid="1657022265078" ${\text{H}}_{\text{2}}\text{S}$

The acid dissociation constant$\mathbf{\left(}{\mathit{K}}_{\mathbf{a}}\mathbf{\right)}$is a numerical representation of an acid's strength in solution. The dissociation constantrole="math" localid="1657022802818" ${\text{K}}_{\text{a}}\text{=}\frac{{\text{[A}}^{\text{-}}{\text{][H}}^{\text{+}}\text{]}}{\text{[HA]}}$is commonly stated as a quotient of the equilibrium concentrations (in$\mathit{m}\mathit{o}\mathit{l}\mathbf{/}\mathit{L}$).

(a)

To write the $K_a$expression of ${\text{CH}}_{\text{3}}{\text{NH}}_{\text{3}}^{\text{+}}$in water, we should write the balanced reaction first –

${\text{CH}}_{\text{3}}{\text{NH}}_{\text{3}}^{\text{+}}{\text{(aq)+H}}_{\text{2}}\text{O(l)}\rightleftharpoons {\text{H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{(aq)+CH}}_{\text{3}}{\text{NH}}_{\text{2}}\text{(aq)}$

Then write the $K_a$expression using the formula below. Note that it only includes aqueous species.

$\begin{array}{c}{\text{K}}_{\text{a}}\text{=}\frac{\text{[product]}}{\text{[reactant]}}\\ {\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{][CH}}_{\text{3}}{\text{NH}}_{\text{2}}\text{]}}{{\text{[CH}}_{\text{3}}{\text{NH}}_{\text{3}}^{\text{+}}\text{]}}\end{array}$

Therefore, the expression is obtained as .${\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{][CH}}_{\text{3}}{\text{NH}}_{\text{2}}\text{]}}{{\text{[CH}}_{\text{3}}{\text{NH}}_{\text{3}}^{\text{+}}\text{]}}$

(b)

To write the$K_a$ expression of $HClO$in water, we should write the balanced reaction first –

${\text{HClO(aq)+H}}_{\text{2}}\text{O(l)}\rightleftharpoons {\text{H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{(aq)+ClO}}^{\text{-}}\text{(aq)}$

Then write the $K_a$expression using the formula below. Note that it only includes aqueous species.

$\begin{array}{c}{\text{K}}_{\text{a}}\text{=}\frac{\text{[product]}}{\text{[reactant]}}\\ {\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{][ClO}}^{\text{-}}\text{]}}{\text{[HClO]}}\end{array}$

Therefore, the expression is obtained as .${\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{][ClO}}^{\text{-}}\text{]}}{\text{[HClO]}}$

(c)

To write the$K_a$ expression of in water, we should write the balanced reaction first –

${\text{H}}_{\text{2}}{\text{S(aq)+H}}_{\text{2}}\text{O(l)}\rightleftharpoons {\text{H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{(aq)+HS}}^{\text{-}}\text{(aq)}$

Then write the$K_a$ expression using the formula below. Note that it only includes aqueous species.

$\begin{array}{c}{\text{K}}_{\text{a}}\text{=}\frac{\text{[product]}}{\text{[reactant]}}\\ {\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{][HS}}^{\text{-}}\text{]}}{{\text{[H}}_{\text{2}}\text{S]}}\end{array}$

Therefore, the expression is obtained as .${\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}_{\text{3}}{\text{O}}^{\text{+}}{\text{][HS}}^{\text{-}}\text{]}}{{\text{[H}}_{\text{2}}\text{S]}}$