Chapter 21: Q21.105P (page 976)

How many seconds does it take to deposit $65.5 g$ of $Zn$ on a steel gate when $21.0 A$ is passed through a ${ZnSO}_{4}$ solution?

Short Answer

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Step 1: Definition

Step by step solution

Calculating the time

A current of $21 . 0 A (A = C / s)$ is passed through a ${ZnSO}_{4}$ solution.

We need to find the time (in seconds) it takes to deposit $65.5 g$ of $Zn$ .

${ZnSO}_{4} \to {Zn}^{2 +} {+ SO}_{4}^{2 -}$

The half-reaction for ${Zn}^{2 +}$ reduction is

${Zn}^{2 +} + 2 e^{-} \to Zn$

- Here we can see that for every mole of $Zn$ deposited, we need $2$ moles of electrons.

The number of moles of $Zn$ deposited is (the molar mass of $Zn$ is $65.38 g / mol$ )

$Moles Zn deposited = \frac{65.5 g}{65.38} = 1.002 mol Zn$

Hence, the number of moles of electrons is

$Moles e^{-} = 1.002 mol Zn \times \frac{2 {mole}^{-}}{1 mol Zn} = 2.004 {mole}^{-}$

Calculating deposit time

- Faraday constant: charge of a mole of electrons $(F = 96485 C / {mol}^{-})$

Now, we will calculate the charge, using the Faraday constant

Charge = Moles $e^{-} \times F$

$= 2.004 {mol}^{-} \times 96485 \frac{C}{{mol}^{-}} = 193355.94 C$

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How many seconds does it take to deposit $65.5 g$ of $Zn$ on a steel gate when $21.0 A$ is passed through a ${ZnSO}_{4}$ solution?

Short Answer

Step by step solution

Calculating the time

Calculating deposit time

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How many seconds does it take to deposit 65.5g ofZn on a steel gate when21.0A is passed through a ZnSO4solution?

Short Answer

Step by step solution

Calculating the time

Calculating deposit time

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Physical Chemistry

The Earths Atmosphere

Nuclear Chemistry

Ionic and Molecular Compounds

Chemical Reactions

Study anywhere. Anytime. Across all devices.

How many seconds does it take to deposit $65.5 g$ of $Zn$ on a steel gate when $21.0 A$ is passed through a ${ZnSO}_{4}$ solution?