Chapter 21: Q21.87P (page 976)

In the electrolysis of molten NaBr,
(a) What product forms at the anode?
(b) What product forms at the cathode?

Short Answer

Expert verified

(a) bromine

(b) sodium

Step by step solution

To find the product forms at the anode

$NaBr \to {Na}^{+} + {Br}^{-}$

(a) In electrolysis of molten salts, the anion turns into a free element. Anions form free elements in the anode. In molten ${NaBr,theanionisBr}^{-} .$

${2Br}^{-} \to {2e}^{-} {+Br}_{2(g)}$

Hence This ${Br}^{-} {turnsintoBr}_{2(g)}$

To find the product forms at the cathode

(b) In electrolysis of molten salts, the cation turns into a free element. Cations form free elements in the cathode. In molten ${NaBr,Na}^{+} isthecation.$

${2Na}^{+} {+2e}^{-} \to {2Na}_{(s)}$

Hence The ${Na}^{+}$ ions turn into sodium metal.

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In the electrolysis of molten NaBr,
(a) What product forms at the anode?
(b) What product forms at the cathode?

Short Answer

Step by step solution

To find the product forms at the anode

To find the product forms at the cathode

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In the electrolysis of molten NaBr,(a) What product forms at the anode?(b) What product forms at the cathode?

Short Answer

Step by step solution

To find the product forms at the anode

To find the product forms at the cathode

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Physical Chemistry

The Earths Atmosphere

Nuclear Chemistry

Chemical Analysis

Organic Chemistry

Inorganic Chemistry

Study anywhere. Anytime. Across all devices.

In the electrolysis of molten NaBr,
(a) What product forms at the anode?
(b) What product forms at the cathode?