Question:Calculate Kc for each of the following equilibria:

aH2g+I2g2HIg;KP=49at730.Kb2SO2g+O2s2SO3g;Kp=2.5×1010at500.K

Short Answer

Expert verified

Answer

Kc and Kp are related to each other through the equation shown below:

Kp=Kc(RT)n

Number of moles in product side and reactant side may vary with different chemical reactions. So, substituting value of in above equation gives following Kc values.

  1. KC = 49
  2. KC = 2.5×1010

Step by step solution

01

Determining Kc for the given equation (a)

Given equation is shown below:

H2g+I2g2HIg

Given

Relation between Kp and Kc can be given in the equation,

KP= 49

KP=KcRTΔn

Were,n=2-2=0

Rearranging the above equation to find Kc then,

Kc=Kp

So, in this reaction value of Kp and Kc are equal.

Equilibrium constant of the given equation is 49

02

Determining Kc for the given equation (b)

Given equation is shown below:

2SO2g+O2s2SO3g

GivenKp=2.5×1010

Relation between Kp and Kc can be given in the equation,

KP=KcRTΔn

Rearranging the above equation to find Kc then,

Kc=Kp

So, in this reaction value of Kp and Kc are equal.

Equilibrium constant of the given equation is 2.5×1010

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