For a problem involving the catalysed reaction of methane and

steam, the following reaction table was prepared:


Explain the entries in the “Change” and “Equilibrium” rows.

Short Answer

Expert verified

The change in amount (pressure) of CO2is + x ass one mole of CO2is formed. The change in pressure of H2is +4x as 4 moles of H2is formed at equilibrium. The

reactant pressure of CH4changes by -x as one mole of CH4reacts.

The change in pressure of H2Ois -2x as two moles of water react to give the

product.

The total pressure of reactants and products will be the sum of initial and change.

Thus, the pressure of CH4=0.30-xandH2O=0.40-2x.

The pressure of role="math" localid="1654924198289" CO2=xand that of H2=4x.

Step by step solution

01

Step 1: What is the change and equilibrium state?

A physical change of a matter is referred to as a change of state. They are reversible alterations that do not entail any changes to the matter's chemical composition. Melting, freezing, sublimation, deposition, condensation, and vaporisation are all examples of state shifts.

The stationary points of the system's total potential energy characterise the equilibrium states of structural and mechanical systems. The principle of stationary potential energy is what this is called.

02

Step 2: Explain the entries in the “Change” and “Equilibrium” rows

As the reaction proceeds, the concentration of products increases and the reactant

decreases. The change in amount (pressure) of CO2is + x as one mole is formed.

The change in pressure of H2is +4x as 4 moles of H2is formed at equilibrium. The

reactant pressure of CH4changes by -x as one mole of CH4reacts.

The change in pressure is -2x as two moles of water react to give a product.

The total pressure of reactants and products will be the sum of initial and change.

Thus, the pressure of CH4=0.30-xandH2O=0.40-2x.

The pressure of CO2=Xand that of H2=4x.

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