Chapter 5: Q5.25P (page 228)

A 93-L sample of dry air cools from $145 ° C$ to $- 22 ° C$ while the pressure is maintained at 2.85 atm. What is the final volume?

Short Answer

Expert verified

Answer

The final volume of the sample is 56 L.

Step by step solution

Ideal gas law

The ideal gas law equation is,

$P V = n R T$

The ideal gas law for the given condition can be written as,

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

(Moles of the sample are fixed)

Determination of final volume

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Here,

$V_{1}$ is the initial volume (93 L).

$V_{2}$ is the final volume.

$T_{1}$ is the initial temperature ( $145 ° C = 418 K$ ).

$T_{2}$ is the final temperature ( $- 22 ° C = 251 K$ ).

$V_{2} = \frac{V_{1}}{T_{1}} \times T_{2} V_{2} = \frac{93 L}{418 K} \times 251 K = 56 L$

Thus, the final volume is 56 L.

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A 93-L sample of dry air cools from $145 ° C$ to $- 22 ° C$ while the pressure is maintained at 2.85 atm. What is the final volume?

Short Answer

Step by step solution

Ideal gas law

Determination of final volume

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A 93-L sample of dry air cools from 145°Cto -22°C while the pressure is maintained at 2.85 atm. What is the final volume?

Short Answer

Step by step solution

Ideal gas law

Determination of final volume

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Kinetics

Chemical Reactions

Ionic and Molecular Compounds

Nuclear Chemistry

Chemistry Branches

Chemical Analysis

Study anywhere. Anytime. Across all devices.

A 93-L sample of dry air cools from $145 ° C$ to $- 22 ° C$ while the pressure is maintained at 2.85 atm. What is the final volume?