Convert the following:

(a) 76.8 cmHg to atm (b) 27.5 atm to kPa

(c) 6.50 atm to bar (d) 0.937 kPa to torr

Convert the unit from cmHg to mmHg,

$\text{1} \text{cmHg =} \text{10} \text{mmHg}$

$\text{76.8} \text{cmHg} \times \frac{\text{10} \text{mmHg}}{\text{1} \text{cmHg}} \text{=} \text{768} \text{mmHg}$

$\text{atm} \text{=} \text{760} \text{mmHg}$

The conversion of $\text{768} \text{mmHg}$to atm is,

$\text{768} \text{mmHg×}\frac{\text{1 atm}}{\text{760} \text{mmHg}} \text{=} \text{1.01} \text{atm}$

Thus, the pressure in the atm unit is 1.01 atm.

$\text{101.325} \text{kPa} \text{=} \text{1} \text{atm}$

The conversion of 27.5 atm to kPa is,

$\text{27.5} \text{atm} \times \frac{\text{101.325} \text{kPa}}{\text{1} \text{atm}} \text{=} \text{2786} \text{kPa}$

Thus, the pressure in the kPa unit is 2786 kPa

$\text{atm} \text{=} \text{1.01325} \text{bar}$

The conversion of 6.50 atm to bar is,

$\text{6.5} \text{atm} \times \frac{\text{1.01325} \text{bar}}{\text{1} \text{atm}} \text{=} 6.59 \text{bar}$

Thus, the pressure in bar unit is 6.59 bar.

Convert kPa into atm,

$\text{101.325} \text{kPa} \text{= 1atm}$

$0.937 \text{kPa×}\frac{\text{1 atm}}{\text{1} 01.325 \text{kPa}} \text{=} 0.009247\text{atm}$

The conversion of 0.009247 atm to torrs is,

1 atm = 760 torr

$0.009247\text{atm} \times \frac{\text{760} \text{torr}}{\text{1} \text{atm}} \text{=} 7.03 \text{torr}$

Thus, the pressure in torr unit is 7.03 torr.