The phase diagram for substance A has a solid-liquid line with a positive slope, and that for substance B has a solid-liquid line with a negative slope. What macroscopic property can distinguish A from B?

Short Answer

Expert verified

The density of the compounds A and B in their solid and liquid state can be used to distinguish between compound A and B. The compound A will have a density of solid more than that of liquid whereas for the compound B, the density of the liquid is more than solid.

Step by step solution

01

Phase transition

As per the phase diagram, the positive slope between the pressure and temperature denotes that with an increase in temperature, the pressure increases for the co-existence of solid and liquid.

The effect of the pressure and temperature on the volume (or density) can be understood by this equation:

V=nRTP

02

 Step-2: Change in volume/ density

Now, for a positive slope, with a more increase in temperature, there is less increase in pressure. It means that the volume of the liquid will be more than solid during the fusion of the compound. This means that the liquid will have less density than the solid.

Now, for a negative slope, with a more increase in temperature, there is less decrease in pressure. It means that the volume of the liquid will be less than solid during the fusion of the compound. This means that the liquid will have more density than the solid.

03

Step-3: Difference in the density during phase transition

As during the phase transition, compound A have more solid density than that of the liquid whereas, for the compound B, the density of liquid is more than solid, the density (macroscopic property) can be used to distinguish between the two

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Why is the heat of fusion (ΔHfus)of a substance smaller than its heat of vaporization(ΔHvap) ?

(b) Why is the heat of sublimation (ΔHsubl)of a substance greater than its(ΔHvap) ?

(c) At a given temperature and pressure, how does the magnitude of the heat of vaporization of a substance compare with that of its heat of condensation?

One of the most important enzymes in the world— nitrogenase, the plant protein that catalyzes nitrogen fixation— contains active clusters of iron, sulfur, and molybdenum atoms. Crystalline molybdenum (Mo) has a body-centered cubic unit cell (d of Mo is 10.28g/cm3).

(a) Determine the edge length of the unit cell.

(b) Calculate the atomic radius of Mo.

Question: Is it possible for a salt of formula AB3 to have a face-centered cubic unit cell of anions with cations in all the eight available holes? Explain

Rank the following in order of decreasing surface tension at a given temperature, and explain your ranking: (a) CH3OH (b) CH3CH3(c) CH2O

Use the Figure to answer the following:

]

a) Carbon dioxide is sold in steel cylinders under pressures of approximately 20atm. Is there liquid CO2in the cylinder at room temperature (~20oC)? At 40oC?At-40oC? At -120oC?

b) Carbon dioxide is also sold as solid chunks, called dry ice, in insulated containers. If the chunks are warmed by leaving them in an open container at room temperature, will they melt?

c) If a container is nearly filled with dry ice and then sealed and warmed to room temperature, will the dry ice melt?

d) If dry ice is compressed at a temperature below its triple point, will it melt?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free