Chapter 19: Q19.96P (page 875)

Write a balanced equation for the reaction of ${Zn(H}_{2} {O)}_{4}^{2 +}$ in aqueous $NaCN$ .

Short Answer

Expert verified

The balanced equation for the reaction of $Zn {(H_{2} O)}_{4}^{2 +}$ in aqueous $NaCN$ is –

$Zn {(H_{2} O)}_{4}^{2 +} {(aq) + 4CN}^{-} (aq) ⇌ {Zn(CN)}_{4}^{2 -} {(aq) + 4H}_{2} O(l)$

Step by step solution

Concept Introduction

A chemical equation is a representation of a chemical process in the form of components. A balanced chemical equation is one in which the number of atoms in all of the molecules is equal on both sides of the equation.

Balanced Equation for ZnH2O42 +

First mention that the coordination number for $Zn(II)$ is $4$ . Thus, when $Zn {(H_{2} O)}_{4}^{2 +}$ reacts with $NaCN$ , there can't be more than role="math" localid="1663626610069" ${4 CN}^{-}$ ions around $Zn(II)$ .

The reaction is as follows –

$Zn {(H_{2} O)}_{4}^{2 +} (aq) + 4 {CN}^{-} (aq) \Leftrightarrow Zn (CN)_{4}^{2 -} (aq) + 4 H_{2} O (l) K_{f} = \frac{[Zn (CN)_{4}^{2 -}]}{[Zn {(H_{2} O)}_{4}^{2 +}] \times {[{CN}^{-}]}^{4}}$

Liquid and solid compounds are not included in the equilibrium expression.

Therefore, the balanced equation is :

$Zn {(H_{2} O)}_{4}^{2 +} {(aq) + 4CN}^{-} (aq) \Leftrightarrow {Zn(CN)}_{4}^{2 -} {(aq) + 4H}_{2} O(l)$ .

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Write a balanced equation for the reaction of ${Zn(H}_{2} {O)}_{4}^{2 +}$ in aqueous $NaCN$ .

Short Answer

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Concept Introduction

Balanced Equation for ZnH2O42 +

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Write a balanced equation for the reaction ofZn(H2O)42 +in aqueous NaCN.

Short Answer

Step by step solution

Concept Introduction

Balanced Equation for ZnH2O42 +

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

Chemistry Branches

Kinetics

Chemical Analysis

Physical Chemistry

Ionic and Molecular Compounds

Study anywhere. Anytime. Across all devices.

Write a balanced equation for the reaction of ${Zn(H}_{2} {O)}_{4}^{2 +}$ in aqueous $NaCN$ .