Chapter 19: Q19.98P (page 875)

Write a balanced equation for the reaction of $Al {(H_{2} O)}_{6}^{3 +}$ in aqueous $KF$ .

Short Answer

Expert verified

The balanced equation for the reaction of $Al {(H_{2} O)}_{3}$ in aqueous is KF given below. $Al {(H_{2} O)}_{6}^{3 +} {+ 6F}^{-} ⇌ {AlF}_{6}^{3 -} {+ 6H}_{2} O(l)$ .

Step by step solution

Concept Introduction

A chemical equation is a representation of a chemical process in the form of components. A balanced chemical equation is one in which the number of atoms in all of the molecules is equal on both sides of the equation.

Writing the balanced equation

To overcome this problem, we must first point out that the coordination number for $Al(III)$ is 6. Thus, when $Al {(H_{2} O)}_{6}^{3 +}$ reacts with , $KF$ the maximum number of $F^{-}$ coordinated to $Al (III)$ will be six.

$Al {(H_{2} O)}_{6}^{3 +} + 6 F^{-} ⇌ {AlF}_{6}^{3 -} + 6 H_{2} O (l) K_{f} = \frac{[{AlF}_{6}^{3 -}]}{[Al {(H_{2} O)}_{6}^{3 +}] \times {[F^{-}]}^{6}}$

Liquid and solid substances are not included in the K_f expression.

Therefore, the balanced equation is:

$Al {(H_{2} O)}_{6}^{3 +} {+ 6F}^{-} ⇌ {AlF}_{6}^{3 -} {+ 6H}_{2} O(l)$

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Write a balanced equation for the reaction of $Al {(H_{2} O)}_{6}^{3 +}$ in aqueous $KF$ .

Short Answer

Step by step solution

Concept Introduction

Writing the balanced equation

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Write a balanced equation for the reaction of $Al {(H_{2} O)}_{6}^{3 +}$ in aqueous $KF$ .