Chapter 16: Q16.59 P (page 731)

For the reaction $A (g) + B (g) \to A B (g)$ , how many unique collisions between A and B are possible if 1.01 mol of A(g) and 2.12 mol of B(g) are present in the vessel?

Short Answer

Expert verified

There are $7.46 \times 10^{47}$ possible collisions between particles A and B.

Step by step solution

Step 1: The number of A and B particles

A material has $6.022 \times 10^{23}$ particles per mole. Then, as follows, calculate the number of particles in 1.01 moles A:

$T h e n u m b e r o f A p a r t i c l e s = 1.01 m o l A \times \frac{{6.022 \times 10}^{23} A}{m o l A} = 6.08222 \times 10^{23} A$

Determine the number of particles in 2.12 moles B in the same way:

$T h e n u m b e r o f B p a r t i c l e s = 2.12 m o l B \times \frac{{6.022 \times 10}^{23} B}{m o l B} = 12.76664 \times 10^{23} B$

Step 2: The number of unique collision between A and B

To find the number of distinct collisions between A and B, multiply the number of particles of each:

$T h e n u m b e r o f u n i q u e c o l l i s i o n = ({6.08222 \times 10}^{23}) \times ({12.76664 \times 10}^{23}) = 7.46 \times 10^{47}$

As a result, there are $7.46 \times 10^{47}$ possible collisions between particles A and B.

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For the reaction $A (g) + B (g) \to A B (g)$ , how many unique collisions between A and B are possible if 1.01 mol of A(g) and 2.12 mol of B(g) are present in the vessel?

Short Answer

Step by step solution

Step 1: The number of A and B particles

Step 2: The number of unique collision between A and B

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For the reaction A(g)+B(g)→AB(g), how many unique collisions between A and B are possible if 1.01 mol of A(g) and 2.12 mol of B(g) are present in the vessel?

Short Answer

Step by step solution

Step 1: The number of A and B particles

Step 2: The number of unique collision between A and B

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Physical Chemistry

Chemistry Branches

Kinetics

Chemical Analysis

Making Measurements

Study anywhere. Anytime. Across all devices.

For the reaction $A (g) + B (g) \to A B (g)$ , how many unique collisions between A and B are possible if 1.01 mol of A(g) and 2.12 mol of B(g) are present in the vessel?