Heats of reaction calculated from bond energies and from heats of formation are often, but not always, close to each other.

a) Industrial ethanol (CH3CH2OH ) is produce by a catalytic reaction of ethylene (H2C=CH2 ) with water at high pressure and temperatures. CalculateΔHorx for this gas-phase hydration of ethylene to ethanol, using bond energies and then using heats of formation.

b) ethylene glycol is produced by the catalytic oxidation of ethylene to ethylene oxide, which then reacts with water to form ethylene glycol:

The ΔHorx for this hydrolysis step, based on heat of formation, is -97kJ/mol. Calculate ΔHorx for the hydrolysis using bond energies.

c) why are two values relatively close for the hydration in part (a) but not close for the hydrolysis in part(b).

Short Answer

Expert verified

a) ΔHorxfor gas-phase hydration of ethylene to ethanol, using bond energies is –

37kJ and ΔHorx for gas-phase hydration of ethylene to ethanol, using heats of

formation is -42kJ.

b) role="math" localid="1659009357148" ΔHorx for the hydrolysis of ethylene oxide using bond energies is 347kJ.

c) The calculated value of ΔHorx (-42kJ) is not the enthalpy of the formation of ethyl alcohol because the reaction does not involve the formation of ethyl alcohol from its constituent elements but using bond energies the value of heat of reaction is -37kJ which is nearly equal to the heat of formation. It is given that the enthalpy of formation of ethylene glycol is -92kJ/mol, and the calculated value of heat of formation from bond energies is 347kJ.

Step by step solution

01

Definition

Bond energy is a measure of the bond strength of a chemical bond and is the amount of energy needed to break the atoms involved in a molecular bond into free atoms.

The amount of heat absorbed or evolved when one mole of a compound is formed from its constituent elements is called heat of formation.

02

ΔHorx for ethyl alcohol

bond energies

C-H 413kJ/mol

C-O 358kJ/mol

O-H 467kJ/mol

C=C 614kJ/mol

C-C 347kJ/mol

Industrial ethanol is produced by a catalytic reaction of ethylene with water at high pressure and temperatures.

CH2=CH2+H2OC2H5OH

Calculation of heat of reaction using bond energies:

ΔHorx=[4×BEC-H+1×BEC=C+2×BEO-H]+[5×BEC-H+1×BEC-C+1×BEC-O+1×BEO-H]  ​​      =[4mol×413kJ/mol+1mol×614kJ/mol+2mol×467kJ/mol]+           [5mol×(-413kJ/mol)+1mol×(-347kJ/mol)+          1mol×(-358kJ/mol)+1mol×(-467kJ/mol)]        =3200+(-3237)        =-37kJ

Calculation of heat of reaction using the heat of formation:

The heat of combustion of ethanol and ethylene is as follows;

C2H5OH+O22CO2+3H2O     ΔHo=-1368kJ.......(1)C2H4+O22CO2+2H2O       ​​​​   ΔHo=-1410kJ.......(2)

Reverse equation (1) and add to equation (2) we get an equation

03

ΔHorx  for ethylene glycol

Calculation of heat of reaction using bond energies:

In the formation of ethylene glycol from ethylene oxide, bonds of reactants are 4 C-H, 1 C-C, 2 C-O and 2O-H and bonds of product is 4 C-H, 2O-H, 2C-O and 1 C-C.

ΔHo=[4×BEC-H+1×BEC-C+2×BEC-O+2×BEO-H]+[4×BEC-H+2×BEO-H+2×BEC-O+1×BEC-C]      =[4mol×413kJ/mol+2mol×347kJ/mol+2mol×358kJ/mol+2×467kJ/mol]+         [4mol×(-413kJ/mol)+2×(-467kJ/mol)+2mol×(-358kJ/mol)          +1mol×(-347kJ/mol)]      =3996+(-3649)       =347kJ

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