Chapter 24: 24.136 CP (page 1107)

In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles: $α, β^{-}, β^{-}, α, α, α, α, β^{-}, α .$ Write a balanced equation for each step.

Short Answer

Expert verified

$_{90}^{232} T h \to_{2}^{4} α +_{88}^{228} R a_{88}^{228} R a \to_{- 1}^{0} β +_{89}^{228} A c_{89}^{228} A c \to_{- 1}^{0} β +_{90}^{228} T h_{90}^{228} T h \to_{2}^{4} α +_{88}^{224} R a_{88}^{224} R a \to_{2}^{4} α +_{86}^{220} R n_{86}^{220} R n \to_{2}^{4} α +_{84}^{216} P o_{84}^{216} P o \to_{2}^{4} α +_{82}^{212} P b_{82}^{212} P b \to_{- 1}^{0} β +_{83}^{212} B i_{83}^{212} B i \to_{- 1}^{0} β +_{84}^{212} P o_{84}^{212} P o \to_{2}^{4} α +_{82}^{208} P b$

Step by step solution

Definition of Nuclear Chemistry

Nuclear chemistry is a branch of chemistry concerned with the “study of changes” in the nucleus of atoms. These nuclear alterations produce nuclear power and radioactivity, and the energy generated by nuclear reactions has a wide range of uses.

Explanation of the balanced equation.

$α$ decay is a radioactive process in which an alpha particle is emitted from a nucleus. $β$ decay A radioactive process in which a beta particle is emitted from a nucleus.

In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles:

First decay process reaction

$({}_{90}^{232}T h e m i t s α e m i s s i o n) :_{90}^{232} T h \to_{2}^{4} α +_{88}^{228} R a$

Second decay process reaction $({}_{88}^{228}R a e m i t s β^{-} e m i s s i o n) :$

${}_{88}^{228}R a \to_{- 1}^{0} β +_{89}^{228} A c$

Third decay process reaction $({}_{89}^{228}A c e m i t s β^{-} e m i s s i o n) :$

${}_{89}^{228}A c \to_{- 1}^{0} β +_{90}^{228} T h$

Forth decay process reaction $({}_{90}^{228}T h e m i t s α e m i s s i o n) :$

${}_{90}^{228}T h \to_{2}^{4} α +_{88}^{224} R a$

Fifth decay process reaction $(_{88}^{224} R a e m i t s α e m i s s i o n) :$

${}_{88}^{224}R a \to_{2}^{4} α +_{86}^{220} R n$

Explanation of the balanced equation.

Sixth decay process reaction $({}_{86}^{220}R n e m i t s α e m i s s i o n) :$

${}_{86}^{220}R n \to_{2}^{4} α +_{84}^{216} P o_{o}$

Seventh decay process reaction $({}_{84}^{216}P o e m i t s α e m i s s i o n) :$

${}_{84}^{216}P o \to_{2}^{4} α +_{82}^{212} P b$

Eighth decay process reaction $({}_{82}^{212} P b e m i t s β^{-} e m i s s i o n) :$

${}_{82}^{212} P b \to_{- 1}^{0} β +_{83}^{212} B i$

Ninth decay process reaction $({}_{83}^{212}B i e m i t s β^{-} e m i s s i o n) :$

${}_{83}^{212}B i \to_{- 1}^{0} β +_{84}^{212} P_{o}$

Tenth decay process reaction $({}_{84}^{212}P o e m i t s α e m i s s i o n) :$

${}_{84}^{212}P o \to_{2}^{4} α +_{82}^{208} P b$

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In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles: $α, β^{-}, β^{-}, α, α, α, α, β^{-}, α .$ Write a balanced equation for each step.

Short Answer

Step by step solution

Definition of Nuclear Chemistry

Explanation of the balanced equation.

Explanation of the balanced equation.

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In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles: α,β-,β-,α,α,α,α,β-,α. Write a balanced equation for each step.

Short Answer

Step by step solution

Definition of Nuclear Chemistry

Explanation of the balanced equation.

Explanation of the balanced equation.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Chemical Reactions

Ionic and Molecular Compounds

Chemistry Branches

Organic Chemistry

Kinetics

Study anywhere. Anytime. Across all devices.

In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles: $α, β^{-}, β^{-}, α, α, α, α, β^{-}, α .$ Write a balanced equation for each step.