Question:Which nuclide(s) would you predict to be stable? Why?

(a)${}^{\mathbf{48}}\mathbf{}\mathbf{\text{K}}$

(b)${}^{\mathbf{79}}\mathbf{\text{Br}}$

(c)$\mathbf{argon}-\mathbf{32}$

Any species of atom that persists for a quantifiable period of time is referred to as a nuclide.

A: a large number

Z is the atomic number (number of protons)

N: the total number of neutrons (A - Z)

The neutron to proton ratio (isfor lighter nuclei.

The neutron to proton ratio increases as the mass of stable nuclei grows.

The ratio of N to Z in heavy nuclei is 1.5:1.

When and Z numbers are even, the nucleus is more stable than when S and Z numbers are odd.

a)

${}^{48}K$
Atomic number of is nineteen
the number of protons is $Z=19$.

The number of neutrons is$Z=19$

Proton to nucleon quantitative relation is

$\begin{array}{rcl}Z& =& \frac{29}{19}\\ & =& 1.53:1\end{array}$

When we verify the graph, we will see that this nuclei has higher quantitative relation than zone of stability, thus it's unstable.

b)

${}^{79}\text{Br}$

Atomic number ofis 35.
The number of protons is$Z=35$.

The number of neutrons is

$\begin{array}{rcl}N& =& A-Z\\ & =& 79-35\\ & =& 44.\end{array}$

Proton tonucleonquantitative relationis :

$\begin{array}{rcl}\frac{\text{N}}{\text{Z}}& =& \frac{44}{35}\\ & =& 1.26:1\end{array}$

This nuclei has thequantitative relationthat'sin zone of stability.

Thus, it's stable.

c)

argon-32
Atomic number of Ar is eighteen.
The number of protons is Z = 32.

The number of neutrons is:

$\begin{array}{rcl}N& =& A-Z\\ & =& 32-18\\ & =& 14.\end{array}$

Proton tonucleonquantitative relationis:

$\begin{array}{rcl}\frac{\text{N}}{\text{Z}}& =& \frac{14}{18}\\ & =& 0.78:1\end{array}$

When wecross-checkthe graph,we willsee that this nuclei has lowerquantitative relationthan zone of stability.

Thus,it'sunstable.

The required graph is: