A rock containsμmol of238U(t1/2=4.5×109yr) and110mol of206Pb Assuming that all the206Pbcomes from decay of the , estimate the rock’s age.

Short Answer

Expert verified

The rock's age is 2.22×109yr

Step by step solution

01

Radioactive decay

The radioactive decay follows the first order kinetics. The relation between half-life and rate constant “k” is:

t1/2=0.693k

02

Estimation of the rock’s age

- The half-life of238Uist1/2=4.5×109yr

- Rock now containsNt=270μmolof238U, and110μmolof206Pb (which means that110μmolof238Udecayed into206Pb )

Therefore, the rock initially contained

N0=270μmol+110μmol238U=380μmol238U

First, let us calculate the decay constant of 238U

t1/2=ln(2)kk=ln(2)t1/2=0.6934.5×109yr=1.54×10-10yr-1


Calculation of the rock's age

lnNtN0=-ktt=-lnNtN0k

=-ln270μmol288U380μmol28U1.54×10-10yr-1=2.22×109yr

Hence the rock's age is 2.22×109yr

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