Chapter 24: Q24.60 P (page 1104)

A $135$ -lb person absorbs ${3.3×10}^{-7} J$ of energy from radioactive emissions.
(a) How many rads does she receive?
(b) How many grays (Gy) does she receive?

Short Answer

Expert verified

$\begin{array}{l} {a)5.39×10}^{-7} rad \\ {b)5.39×10}^{-9} Gy \end{array}$

Step by step solution

The given data

-_{$1rad=0.01J/kg=0.01Gy$}

- The mass of a person is_{$135 lb$}

- Person absorbs_{$3.3 \times 10^{- 7} J$}of energy from radioactive emissions

Subpart (a)

The number of rads

Since 1 rad is $0.01 J / kg$ , first, we have to convert the mass of a person, from lb to_$kg$

_{$\begin{matrix} massofaperson = 135 lb \times \frac{0.453592 kg}{1 lb} \\ = 61.235 kg \end{matrix}$}

So, the number of rads that a person received is

$\begin{matrix} Numberofrad= \frac{{3.3×10}^{-7} J}{61.235kg} × \frac{1rad}{0.01J/kg} \\ {=5.39×10}^{-7} rad \end{matrix}$

Subpart (b)

The number of grays

$\begin{matrix} {Numberofgrays=5.39×10}^{-7} rad× \frac{0.01Gy}{1rad} \\ {=5.39×10}^{-9} Gy \end{matrix}$

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A $135$ -lb person absorbs ${3.3×10}^{-7} J$ of energy from radioactive emissions.
(a) How many rads does she receive?
(b) How many grays (Gy) does she receive?

Short Answer

Step by step solution

The given data

Subpart (a)

Subpart (b)

One App. One Place for Learning.

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A 135-lb person absorbs 3.3×10-7Jof energy from radioactive emissions.(a) How many rads does she receive?(b) How many grays (Gy) does she receive?

Short Answer

Step by step solution

The given data

Subpart (a)

Subpart (b)

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Chemistry Branches

Kinetics

Inorganic Chemistry

Chemical Reactions

Chemical Analysis

Study anywhere. Anytime. Across all devices.

A $135$ -lb person absorbs ${3.3×10}^{-7} J$ of energy from radioactive emissions.
(a) How many rads does she receive?
(b) How many grays (Gy) does she receive?