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Chapter 14: Q107P (page 623)

Write balanced chemical equations for the thermal decomposition of potassium nitrate (oxygen is also formed in both the cases): (a) at low temperature to the nitrite; (b) at high temperature to the metal oxide and nitrogen.

Short Answer

Expert verified

The answer is

a). 2KNO3→2KNO2+O2

b).2KNO3→K2O+N2+102O2

Step by step solution

01

Thermal decomposition reaction

The balanced chemical equation for the reaction at low temperature is given below.

2KNO3→2KNO2+O2

Here the products formed are potassium nitrite and oxygen. The chemical equation is balanced by putting 2 before the potassium nitrate on the reactant side and 2 before nitrite on the product side.

02

Subpart (b)

The balance chemical equation for the reaction is given below.

2KNO3→K2O+N2+102O2

Here the products obtained are potassium oxide, nitrogen and oxygen. The chemical equation here is balanced by balancing the number of oxygen atoms on the product side with those on the reactant side.

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Most popular questions from this chapter

Iodine monochloride and elemental bromine have nearly the same molar mass and liquid density but very different boiling points.

(a) What molecular property is primarily responsible for this difference in boiling point? What atomic property gives rise to it? Explain.

(b) Which substance has a higher boiling point? Why?

Select the stronger bond in each pair:

(a) Cl-Cl or Br-Br

(b) Br-Br or I-I

(c) F-F or Cl-Cl.

Why doesn't the F-F bond strength follow the group trend?

(a) Define the four atomic properties that are reviewed in the Interchapter.

(b) To what do the three parts of the electron configuration ( ) correlate?

(c) Which part of the electron configuration is primarily associated with the size of the atom?

(d) What is the major distinction between the outer electron configurations within a group and those within a period?

(e) What correlation, if any, exists between the group number and the number of valence electrons?

Question: Which Group 5A (15) elements form trihalides? Pentahalides? Explain.

The main reason alkali metal dihalides (MX2) do not form is the high IE2of the metal.

(a) Why is IE2 so high for alkali metals?

(b) The IE2 for Cs is 2255 kJ/mol, low enough for CsF2 to form exothermicallyΔH0f=-125kJ/mol . This compound cannot be synthesized, however, because CsF forms with a much greater release of heatlocalid="1663354802147" (ΔH0f=-530kJ/mol). Thus, the breakdown of CsF2 to CsF happens readily. Write the equation for this breakdown, and calculate the heat of reaction per mole of CsF.
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